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4 years ago

Choose the equation that represents the graph below: (1 point)

Mathematics

1 answer:

nata0808 [166]4 years ago

4 0

It would be A. <span>y = −2x − 4.
Hope this helps!!
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Use the equation √4x+15 - 3√x How many potential solutions are there?

topjm [15]

There is one potential solutions and no extraneous solutions.

7 0

3 years ago

815 gal/h _____ qt /se

kari74 [83]

There are 3260 quarts in 815 US gallons

3 0

3 years ago

Read 2 more answers

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 250 people entered the park, a

pogonyaev

Answer:

100 children

150 adults

Step-by-step explanation:

c- children

a- adults

---------------

we get equations as per question:

1.5c+4a= 750
c+a= 250 ⇒ a= 250- c

1.5c +4(250-c)= 750 ⇒
1.5c- 4c+1000=750 ⇒
2.5 c= 250 ⇒
c= 100
a= 250-100 ⇒
a= 150

Children 100, adults 150

6 0

3 years ago

Consider the function f(x)= 1-|x-1|+|x+1| for -3<x<3. Recall that the absolute function can be represented as a piece wise

Kruka [31]

By the definition for the absolute value,

$|x-1|=\begin{cases}x-1&\text{for }x\ge1\\-(x-1)&\text{for }x$
$|x+1|=\begin{cases}x+1&\text{for }x\ge-1\\-(x+1)&\text{for }x$

So for the compound function $f(x)=1-|x-1|+|x+1|$ , there are three intervals to consider. What happens when $x$ ? when $-1\le x$ ? when $x\ge1$ ?

You have

$f(x)=\begin{cases}1-(-(x-1))+(-(x+1))=-1&\text{for }x$

8 0

4 years ago

The birth rate of a population is b(t) = 2300e0.021t people per year and the death rate is d(t)= 1450e0.018t people per year, fi

Cerrena [4.2K]

Answer:

38,674.This area represents the increase in population over a 10-year period.

Step-by-step explanation:

When graphed over the interval 0 ≤ t ≤ 10, the birth rate is more than the death rate. This means the area between the two curves is the amount of births subtract the amount of deaths. This results in an area which means the increase of the population.

The birth rate is graphed in green and the death rate is graphed in blue.

To find the area, take the integral of the difference of the functions:

$\int\limits^{10}_0 {2300e^{0.021t} - 1450e^{0.018t} } \, dt \\\\\frac{2300e^{0.021t}}{0.021} - \frac{1450e^{0.018t}}{0.018} \\\\(\frac{2300e^{0.21}}{0.021} -\frac{1450e^{0.18}}{0.018} ) - (\frac{2300}{0.021}- \frac{1450}{0.018} ) \\\\135117.12 - 96442.51 \\\\38,674$

7 0

3 years ago