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2 years ago

Solve the equation. Round the solution to two decimal places.

2 answers:

5 0

Subtract the y values to one side then the numbers to the other so as x values to one side then the numbers to the other

-BARSIC- [3]2 years ago

4 0

Answer:

y = -0.71

x = 8

Step-by-step explanation:

Bring variables on one side of the equation

18.3y - 8.4y = -14.6 + 7.6

4.1x - 0.7x = 25.9 + 1.3

Solve for the variable

9.9y = -7

y = -70/99

3.4x = 27.2

x = 8

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Sandra is 4 feet tall and Pablo is 10% taller than Sandra, and machela is 8% taller than Pablo.

Luda [366]

Sandra's Height: 4ft.
Pablo's Height: 4.4ft.
Machela's Height: 4.75ft.

Hope this helps.

4 0

3 years ago

How can 25 e42 n=1 be rewritten?

Marizza181 [45]

Answer:

The 'n = 1' below sigma represents the lower bound. meaning the number from which you start adding.

'25' above sigma is the upper bound.

In general it means adding 42 from 1 to 25 times.

so 42(25).

8 0

2 years ago

Solve the quadratic equation by completing the square. x²+18x+79=0

pogonyaev

$x^2 + 18x=-79 \\ \\ x^2 + 18x+81=2 \\ \\ \boxed{(x+9)^2=2} \\ \\ x+9=\pm \sqrt 2 \\ \\ x=-9 \pm \sqrt{2} \\ \\ \boxed{x=-9+\sqrt{2}, -9-\sqrt{2}}$

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2 years ago

David estimated he had about 20 fish in his pond. A year later, there were about 1.5 times as many fish. The year after that, th

aliya0001 [1]

After 2 years you have 45 fishes!
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3 0

4 years ago

Read 2 more answers

Correct answer gets brainliest

Ilia_Sergeevich [38]

Answer:

sides: isosceles
angles: right

Step-by-step explanation:

At first, lets find the distance from one point to the other.

$d(A,B)=\sqrt{(x_{A}-x_{B} )^2 +(y_{A}-y_{B} )^2 } \\d(A,B)=\sqrt{(2-0 )^2 +(-2-4 )^2 } \\d(A,B)=\sqrt{4 +36 } = \sqrt{40 } = \sqrt{4 * 10 } = 2\sqrt{10}$

The same way, you can find that:

$d(A,C)= 2\sqrt{10}\\d(A,B)= 2\sqrt{20}$

Since the triangle has only its two sides equal to each other (AB = AC),

it's an isosceles one.

As long as the angles are concerned, we gotta "cheat". In other words, we see that:

$AB^2 + AC^2 = (\sqrt{40})^2 + (\sqrt{40})^2 = 40 + 40 = 80\\ AB^2 + AC^2 = 80 = (2\sqrt{20})^2 = BC^2\\AB^2 + AC^2 = BC^2$

By the inverse of pythagorean theorem, we know that if the above equation holds, then we have a right-angled triangle. That is to say that,

A = 90

Since its an isosceles triangle, AB = AC,

B = C = (180 - A)/2 = 45 degrees

7 0

3 years ago