The distance of it away from zero cannot be a negative distance, distance is always positive therefor the absolute value will always be positive.
Short answer: no, absolute value is always positive
I hope this helps :)
Answer:
Step-by-step explanation: x - 6
The given equation can be re-written as y = ---------
-3
Arbitrarily choose x = 0. Then:
x - 6 0-6
y = --------- = ----------- = 2, so (0, 2) is a point on the graph which is also the
-3 -3 y-intercept
Arbitrarily choose x = 6. Then y = 0, and (6, 0) is another point on the graph
which happens to be the x-intercept
arbitrarily choose x = 12. Then y = (12 - 6) / (-3) = -2. Then (12, -2) is
another point on the
graph.
Plot (12, -2), (6, 0) and (0, 2). Draw a line through these three points.
90 - (90 × .7) = $27
hope this helps
Given the slope, m = -2/3, and the x-intercept, (3,0):
Use these values and plug into the slope-intercept form to solve for the y-intercept, b:
y = mx + b
0 = -2/3(3) + b
0 = -2 + b
Add 2 to both sides to isolate b:
0 + 2 = -2 + 2 + b
2 = b
Now that we have our slope, m = -2/3, and the y-intercept, 2
The linear equation in slope-intercept form is:
y = -2/3x + 2
Please Mark my answers as the Brainliest, if you find this helpful :)
Step-by-step explanation:
LET THE Point 1 A and point 2 is B
(AB) ^2=(-9-(-3))^2+ (5-(-6))^2+(-4-7)^2=278
AB=16.67 length unit
Midpoint
X=-9-3/2 =-6
Y=5-6/2=-0.5
Z=-4+7/2=-1.5
