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julia-pushkina [17]
3 years ago
10

Ten bags of cocoa beans cost 350 cedis. Find the cost of 6 bags

Mathematics
1 answer:
Nonamiya [84]3 years ago
8 0

Answer:

210 cedis

Step-by-step explanation:

If ten bags of cocoa beans cost 350 cedis then you need to find the cost of one bag of cocoa beans

= 35 cedis

350 × 0.1 = 35

then multiply by 6 to get the cost of six bags

35 × 6 = 210

six bags of cocoa beans will cost 210 cedis.

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Assuming that the room is rectangle and carpet is rectangle
area=legnth times width
legnth=longer than width
12  is longer than 8
12ft=legnth
8ft=width
 
now convert to yards
1 yard=3 feet
1 foot=1/3 yard
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multiply
 
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he​ half-life for a link on a social network website is 2.6 hours. Write an exponential function T that gives the percentage of
pychu [463]

Answer:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining= [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

Step-by-step explanation:

Previous concepts

The half-life is defined "as the amount of time it takes a given quantity to decrease to half of its initial value. The term is most commonly used in relation to atoms undergoing radioactive decay, but can be used to describe other types of decay, whether exponential or not".

Solution to the problem

The half life model is given by the following expression:

A(t) = A_o (1/2)^{\frac{t}{h}}

Where A(t) represent the amount after t hours.

A_o represent the initial amount

t the number of hours

h=2.6 hours the half life

And we want to estimate the % after 5.5 hours. On this case we can begin finding the amount after 5.5 hours like this:

A(5.5) = A_o (1/2)^{\frac{5.5}{2.6}}

Now in order to find the percentage relative to the initial amount w can use the definition of relative change like this:

% Remaining = \frac{|A_o - A_o(1/2)^{\frac{5.5}{2.6}}|}{A_o} x100

We can take common factor A_o and we got:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining = [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

5 0
4 years ago
What is the least common denominator of 4/x * -4/2x^2?
Vanyuwa [196]
The least common denominator would be 2x^2
that is because you would have to multiply the first fraction by 2x
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8x /2x^2 * -4/2x^2
Then you would complete it 

Hope this helps :)
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3 years ago
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