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inn [45]
3 years ago
15

What is the least common denominator of 4/x * -4/2x^2?

Mathematics
2 answers:
Vanyuwa [196]3 years ago
6 0
The least common denominator would be 2x^2
that is because you would have to multiply the first fraction by 2x
but you can't just somehow simplify 2x^2, it wouldn't be right
4/x * -4/2x^2
2x*4/(2x*x) * -4/2x^2
8x /2x^2 * -4/2x^2
Then you would complete it 

Hope this helps :)
Illusion [34]3 years ago
5 0
Answer: 2x^2

Justification:

First we must make the expressions clear.

It seems you are asking about the least common denominator of 4/x and - 4/ (2x^2).

I will not simpligy the second denominator and will find the least common denominator of x and 2x^2.

The least common factor is the simplest (smallest) factor that contain all the factors given.

So, the least common denominator of both x and 2x^2 is the simplest monomial that contains them.

To find that least common factor you take the  product of:

- least common multiple of the coefficients: in this case the coefficients are 1 and 2, so the least common coefficient is 2.

- the product of the different letter raised to the highest power: in this case the only letter is x and the highest power is 2, so it is x^2

Therefore the lease common denominator is the product of 2 and x^2 which is 2x^2.
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3 years ago
Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly​ low, μ- 2σ ​, and the maximum val
allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\

Using the binomial distribution: \mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186

In this the maximum value which is significantly​ low, \mu-2\sigma, and the minimum value which is significantly​ high, \mu+2\sigma, that is equal to:

\mu-2\sigma = 22.32 - 2(4.1186) = 14.0828 \approx 14.08\\\\\mu+2\sigma = 22.32 + 2(4.1186) = 30.5572 \approx 30.56

3 0
3 years ago
Find the inverse function of <br><br> y=x^5+9
ollegr [7]

Answer:

\sqrt[5]{x - 9}

Step-by-step explanation:

y=x^5+9

To find inverse function make x the subject, first:

y=x^5+9

y - 9 = x^5

x = \sqrt[5]{y - 9}

y^{-1}  = \sqrt[5]{x - 9}

so  inverse function of y=x^5+9 is  \sqrt[5]{x - 9}

3 0
2 years ago
Read 2 more answers
What Is the answer to 10ac-x/11=-3
cestrela7 [59]
  1. Multiplty both sides by 11. 11 times 11 cancels out, 11 times -3 equals -33. You should get 10ac - x = -33
  2. Add  x  to both sides:   10 a c = x − 33
  3. Divide both sides by  10 c :   a = x − 33 /10c

revised tada!

4 0
3 years ago
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