The answer would be 0.4375 pounds
Start by converting your two equations into slope-intercept form.
3x - 3y = -9
-3y = -3x -9 Subtract 3x from both sides
y = x +3 Divide both sides by -3
2x + y = 9
y = -2x + 9 Subtract 2x from both sides.
Then graph both lines (in which case the point where they intersect is the solution) or substitute in each point until both equations are true.
In this case the solution is (2,5); both equations become 5=5 when you substitute in the point's coordinates.
Answer:
the height of the tree to the nearest tenth of a meter is 13.8 meters
Step-by-step explanation:
The computation of the height of the tree is shown below:
Given that
Distance from the tree is 10 meters
And, the angle of elevation of the tree is 54 degrees
Now here we used the trigonometry
![tan \theta = \frac{Height}{distance} \\\\tan 54^{\circ} = \frac{height}{10}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cfrac%7BHeight%7D%7Bdistance%7D%20%5C%5C%5C%5Ctan%2054%5E%7B%5Ccirc%7D%20%3D%20%5Cfrac%7Bheight%7D%7B10%7D)
So, the height is
= 10 × 1.38
= 13.8 meters
hence, the height of the tree to the nearest tenth of a meter is 13.8 meters