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kotegsom [21]
2 years ago
15

Help ASAP I’ll give brainliest don’t answer of u do not know thank u Sm:)

Mathematics
2 answers:
Ber [7]2 years ago
3 0
The answer to the question is >
IceJOKER [234]2 years ago
3 0
Hopefully this helps!

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A discount voucher offering 15% off is used to pay a bill. After using the voucher, the bill is reduced to £36.72.
Elena-2011 [213]

We can use the is/of=p/100 method for this problem. Since it's 15% off, this would mean that the bill is 85% of what it was initially. Plug the values into the is/of=p/100 formula.

36.72/x = 85/100

Solve  for x.

x=36.72/0.85

x=43.2

So, the bill was $43.20 before applying the voucher discount of 15% off.

3 0
3 years ago
Read 2 more answers
Ten more than 6 times a number is 4 less than 4 times the number. Please help me!!
Y_Kistochka [10]
10+6x=4x-4
6x-4x=-4-10
     2x=-14
      x-7
10=6(-7)=-32
4(-7)-4=-32
         =-32
6 0
3 years ago
A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

7 0
3 years ago
Please help ASAP!! Will mark brainliest!!
Sergio [31]

The answer is 10 because all the angles are equal making it a equilateral triangle.

Therefore, the sides are all equal to one another, 3x - 8 = 5x - 20.

You just solve for x and get 6. You then plug in 6 for x and evauluate the equation, getting 10.

3 0
3 years ago
Read 2 more answers
The area of a sector of an circle of a radius 5 cm, formed by an arc of length is 3.5cm. what is the answer
Natali5045456 [20]

Answer:

8.75cm²

Step-by-step explanation:

First we need to find the angle subtended by the arc

L = theta/360 * 2pir

3.5 = theta/360 * 2*3.14(5)

3.5 = theta/360 * 31.4

theta/360 = 3.5/31.4

theta/360 = 0.11146

theta = 0.11146 * 360

theta = 40.13 degrees

Area of the sector = theta/360 * pir^2

Area of the sector = 40.13/360 * 3.14*25

Area of the sector = 40.13/360 * 78.5

Area of the sector  = 8.75cm

Hence the area of the sector is 8.75cm²

5 0
2 years ago
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