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Vadim26 [7]
3 years ago
9

Analyze the diagram below and complete the instructions that follow.

Mathematics
1 answer:
ozzi3 years ago
6 0
According to the image:
the right hexagonal pyramid surface area is given by the following formula:

S = 3√3 / 2) a² + 3a √h²+3a²/4
a = the base edge
h = the height of the pyramid

looking at the image  a =6m,  h =21m - 7m= 14m

so the surface area is S = 3√3 / 2) 6² + 3*6√14²+3*6²/4 =93.53+ 14.93=108.46 m²

for the another one
the figure is a prism hexagonal
its surface area is 
SA= 6ah +3√3 a²
a= base edge, h =height
in our case a =6m and h = 7m
so SA= 6*6*7 + 3√3 * 6²= 252 + 187 = 439 m²

finally, the surface area of the complete image is 
ST= S + SA = 108.46 m² + 439 m² = 547.52 m²
it is so approximate
 to <span>B. 615.53 m2
look at the image</span>

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Divide 28 bottles of water into two groups so the ratio is 3 to 4. Be sure to show your work.
tatyana61 [14]

Answer:

12:16

Step-by-step explanation:

28 split into two groups could be 12 : 16. To check the work, see if 3/4 is equal to 12/16. It is, so this is the accurate ratio, as 12 + 16 = 28 and 12/16 = 3:4.

4 0
3 years ago
Estimate the solution of the system x+y=4 2x-y=6 by sketching a graph of each linear function. Then solve the system algebraical
Juli2301 [7.4K]

Answer:

(10/3, 2/3)

Step-by-step explanation:

You may find it easier to write these two equations x+y=4 2x-y=6 in a column:

x+y=4

2x-y=6

Adding these together will eliminate y:

3x = 10.  Then x = 10/3.

Substituting 10/3 for x in the first equation results in:

10/3 + y = 4

Clear fractions by multiplying all three terms by 3:

10 + 3y = 12

Then 3y = 2, and y = 2/3.

The solution is (10/3, 2/3)

8 0
3 years ago
Heeelp<br> the first choices are linear or non linear<br> the second is increasing or decreasing
slega [8]
It’s non linear and it’s decreasing
5 0
3 years ago
If you know the length of sides b and c of a right triangle, which equation represents the length of side a, according to the Py
Reptile [31]

Answer:

A=SqRt(c^2-b^2)

Step-by-step explanation:

a^2 + b^2 = c^2

rearrange to solve for a^2

a^2= c^2-b^2

take the square root of each side

a= square root (c^2-b^2)

3 0
3 years ago
Suppose you choose a team of two people from a group of n &gt; 1 people, and your opponent does the same (your choices are allow
jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

 \left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right     i^{3}

Step-by-step explanation:

selecting the first team from n people we have \left(\begin{array}{ccc}n\\1\\\end{array}\right)  = n possibility and choosing second team from the rest of n-1 people we have \left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1

As { A, B} = {B , A}

Therefore, the total possibility is \frac{n(n-1)}{2}

Since our choices are allowed to overlap, the second team is \frac{n(n-1)}{2}

Possibility of choosing both teams will be

\frac{n(n-1)}{2}  *  \frac{n(n-1)}{2}  \\\\= [\frac{n(n-1)}{2}] ^{2}

We now have the formula

1³ + 2³ + ........... + n³ =[\frac{n(n+1)}{2}] ^{2}

1³ + 2³ + ............ + (n-1)³ = [x^{2} \frac{n(n-1)}{2}] ^{2}

=\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] =   [\frac{n(n-1)}{2}]^{3}

4 0
4 years ago
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