The y intercept is where m=0. Hence, set m=0 and solve for c:
c=0.05(0)+4.95
c=4.95
X fourths minus seventeen
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
The slope-intercept form: y = mx + b
We have the slope m = 9, therefore: y = 9x + b.
Next. We have the table:
x | -5 | -2 | 1 | 3 | 4 |
y |-46|-19| 8 |26|35|
(1, 8) → x = 1, y = 8
substitute the values of x and y to the equation:
8 = 9(1) + b
8 = 9 + b |-9
b = -1
Answer: y = 9x - 1 → y-intercept is -1.
Answer:
Step-by-step explanation:
