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2 years ago

8

Find the perimeter of a triangle 20cm and 29cm

2 answers:

andrey2020 [161]2 years ago

6 0

Answer:

Unknown unless you give the amount of cm for the last side

bagirrra123 [75]2 years ago

5 0

Answer:

Unclear.

To find the perimeter you need all three sides of the triangle. You have only given two.

All you need to do is add up all three sides and you have your perimeter.

Formula: <u>P=a+b+c</u>

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Help pleaseee, thank you.

Nookie1986 [14]

Answer:9/40

Step-by-step explanation:

You’ll use the LCM which will be 40 so George 2/5 will be 16/40 and Tyler 3/8 will be 15/40 add those together and it’ll be 31/40 leaving Lance to do the last 9/40

4 0

3 years ago

PLSS HELP IF YOU TURLY KNOW THISS

dangina [55]

Answer:

$\frac{0.3x - 2.1}{3} = 0.4 \\ 0.3x - 2.1 = 0.4 \times 3 \\ 0.3x - 2.1 = 0.12 \\ 0.3 x = 0.12 + 2.1 \\ 0.3x = 2.22 \\ x = \frac{2.22}{0.3} \\ x = 7.4$

6 0

3 years ago

Read 2 more answers

the length of a rectangle is 2 more than the width and the perimeter is 80. find the dimensions of the rectangle

4vir4ik [10]

Let width = x then
2x+ 2(x + 2) = 80
4x + 4 = 80
4x = 76
x = 19

so the width is 19 and the length is 21 answer

5 0

3 years ago

Read 2 more answers

What is the value of x to the nearest degree?<br><br> 48 <br> 42 <br> 84 <br> 24

Cerrena [4.2K]

Answer:

The value of the angle x is 48°.

Step-by-step explanation:

Base of the triangle = 10

Height of the triangle = 11

$\tanx =\frac{Height}{Base}$

$\tanx =\frac{11}{10}=1.1$

$x =\tan^{-1}1.1=47.7263^o\approx 48^o$

The value of the angle x to the nearest degree is 48°.

8 0

3 years ago

What is an equation of a line which passes through (6,9) and is perpendicular to the line whose equation is 4x − 6y = 15?

Svetllana [295]

<u>Given:</u>

The equation of the line passes through the point (6,9) and is perpendicular to the line whose equation is $4 x-6 y=15$

We need to determine the equation of the line.

<u>Slope</u>:

Let us convert the equation to slope - intercept form.

$-6 y=15-4x$

$y=\frac{2}{3}x-\frac{5}{2}$

From the above equation, the slope is $m_1=\frac{2}{3}$

Since, the lines are perpendicular, the slope of the line can be determined using the formula,

$m_1 \cdot m_2=-1$

$\frac{2}{3} \cdot m_2=-1$

$m_2=-\frac{3}{2}$

Therefore, the slope of the equation is $m=-\frac{3}{2}$

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the point (6,9) and the slope $m=-\frac{3}{2}$ in the above formula, we get;

$y-9=-\frac{3}{2}(x-6)$

Simplifying the terms, we get;

$2(y-9)=-3(x-6)$

$2y-18=-3x+18$

$3x+2y=36$

Thus, the equation of the line is $3x+2y=36$

3 0

3 years ago