$Coconut = 2 x $Banana
$Banana = (1/3) x $Grapefruit
$Coconut = 2 x (1/3) x $Grapefruit
$Coconut = 2/3 x $Grapefruit
One coconut costs 2/3 what a grapefruit costs or "is 2/3 as expensive" to be congruent with the question.
Answer:
C = 0.5t + 12. Independent variable is t and the dependent variable is C.
Step-by-step explanation:
$12 is constant, and then $0.50 is multiplied to the amount of toppings (t). So C= 0.5t + 12 and the cost is dependent on the amount of toppings.
The cosine of 30° is √3 / 2.
Since cosine is Adjacent over Hypotenuse, Hypotenuse = (2 / √3) * 9 = 18 / √3.
The cosine of 45° is √2 / 2.
Therefore, X = (2 / √2) * (18 / √3) = 36 / √6 = 18 / √1.5 = C
Answer:
the conditional probability that X = 1 , X = 2 and X = 3 is 0.7333 (73.33%) , 0.25 (25%) and 0.0167 (1.67%) respectively
Step-by-step explanation:
a player wins money when i>0 then defining event W= gain money , then
P(W) = p(i>0) = p(1)+p(2)+p(3)
then the conditional probability can be calculated through the theorem of Bayes
P(X=1/W)= P(X=1 ∩ W)/P(W)
where
P(X=1 ∩ W)= probability that the payout is 1 and earns money
P(X=1 / W)= probability that the payout is 1 given money was earned
then
P(X=1/W)= P(X=1 ∩ W)/P(W) = P(X=1) / P(W) = p(1) /[p(1)+p(2)+p(3)] = 11/40 /(11/40+3/32+1/160
) = 0.7333 (73.33%)
similarly
P(X=2/W)=p(2) /[p(1)+p(2)+p(3)] = 3/32 /(11/40+3/32+1/160
) = 0.25 (25%)
P(X=3/W)=p(2) /[p(1)+p(2)+p(3)] = 1/160 /(11/40+3/32+1/160
) = 0.0167 (1.67%)
