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Papessa [141]
2 years ago
11

Mackenzie picked 20 strawberries, 5 blueberries, and 15 raspberries. What was the ratio of the number of strawberries to the tot

al number of berries she picked?
Mathematics
1 answer:
Korvikt [17]2 years ago
4 0

Answer:

20:40

Step-by-step explanation:

Because part of the ratio is the total number of berries, we need to add up all of the berries.

20+15+5=40

The number of strawberries picked is 20, so the ratio is 20:40

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The answer would be 98

7+7=14
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Solve this question in the following photo​
katovenus [111]

Answer:

55/43

Step-by-step explanation:

(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43

6 0
2 years ago
Which of the binomials below is a factor of this trinomial?
mart [117]

Hi there! :)

Answer:

\huge\boxed{D,  x -4}

---- Starting with: ----

x² - 10x + 24

Since we have a leading coefficient of 1, simply find two numbers that sum up to -10 and multiply into 24.

By guessing and checking, we get the numbers -6 and -4. Put these into factors:

(x - 6)(x - 4)

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8 0
3 years ago
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Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
3 years ago
What is the difference between infinite solutions and all real numbers?
igomit [66]

Answer:

Real numbers are like pi, 4, -3, 1/3, 1.25, -3468374, ......

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like 2+2 = 3 + 2

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It doesn't make sense at all

Hope it helps :)

6 0
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