Remark
You'll see it a whole lot easier if you make a substitution so that it looks like something you have already seen
Solution
let y = x^2
x^4 = x^2 * x^2
x^4 = y * y
x^4 = y^2
Now the expression becomes
y^2 + 8 y - 9 = z
(y + 9)(y - 1) = z
Now put the x^2 back in.
(x^2 + 9) ( x^2 - 1) = z
x^2 - 1 becomes x + 1 and x - 1. At this level x^2 + 9 can't be factored.
Answer
(x^2 + 9) (x + 1)(x - 1)
9514 1404 393
Answer:
$2038.85
Step-by-step explanation:
The value of the loan at that point is given by ...
A = P(1 +rt) . . . . . Principal P, rate r, time t (years)
A = $1850(1 + 0.1225·(10/12)) = $2038.85
Ricardo will have paid back $2038.85 at the end of the loan period.
_____
<em>Additional comment</em>
We assume that the loan accrues simple interest and that the amount due is the sum of principal and interest at the end of the loan period.
The question is not specific as to whether interest compounds, or whether intermediate (monthly) payments are made. There are many possible ways the loan could be repaid, generally involving different amounts for the different terms.
60 divided by 1/5 (.2) is 300
Answer:
A=535.93
Step-by-step explanation:
A=P(1+r)^t
A=500[(1+0.07/4)]^4
A=535.93