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EleoNora [17]
2 years ago
5

Isla flipped a coin 30 times. The coin landed heads up 9 times and tails up 21 times. Part A: Based on the results, what is the

experimental probability of the coin landing heads up? Show your work. (5 points) Part B: What is the theoretical probability of the coin landing heads up? Show your work. (5 points).
Mathematics
1 answer:
lisabon 2012 [21]2 years ago
3 0

The theoretical probability of the coin landing heads up is 0.5.

We have given that,Isla flipped a coin 30 times.

The coin landed heads up 9 times and tails up 21 times.

We have to determine,What is the theoretical probability of the coin landing heads up?

<h3>What is the meaning of theoretical probability?</h3>

Theoretical probability is probability that is determined on the basis of reasoning. Experimental probability is probability that is determined on the basis of the results of an experiment repeated many times.

By using the theoretical probability concept assuming it means a percentage, so to turn a fraction into a percentage the top by the bottom (9÷30) and multiply by 100

.\frac{9}{30}* 100=90%

And, to turn a fraction into a percentage the top by the bottom (9÷30) and multiply by 100.

\frac{9}{21} *100=42.86%

It depends on if it wants a basic probability on how many times it will land on heads, if it does use 42.86%. If it wants a probability out of 30 it's 30%.

The theoretical probability of the coin landing heads up is given by,

=\frac{50}{100}\\ =\frac{1}{2} \\=0.5

Hence, The theoretical probability of the coin landing heads up is 0.5.

To learn more about the probability visit:

brainly.com/question/8652467

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Answer: An arithmetic sequence is of the form:

aₙ = a₀ + (n -1)*d

So the difference between a term and the nextone is always the same, and in our case the numbers are 5,8,13,21,34,55.

The distance between the numbers is not constant, so this is not a arithmetic sequence.

a geometric sequence is of the form: aₙ = a*rⁿ

So the therms grow exponentially.

here a₀ = a*r⁰ = a = 5.

a₁ = a*r¹ = 5*r = 13, then r = 13/5 = 2.6

a₂ = a*r² = 5*2.6*2.6 = 33.8, so here we can see that this is not our series, so our series isn't geometric.

So the answer for the first part is neither.

Now, the sequence is  5,8,13,21,34,55, ...

you can see that

5 + 8 = 13

13 + 8 = 21,

21 + 34 = 55

So our sequence is of the form: aₙ = aₙ₋₁ + aₙ₋₂.

then, the next term will be: 55 + 21= 76.

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3 years ago
What is the circumference of a 9 m circle?
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Question is in the image​
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Answer:

4.

Step-by-step explanation:

y = -2x + 3

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8 0
3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
3 years ago
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