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Inessa05 [86]
3 years ago
13

Surface area triangle prism 3in ,3in ,3in 2.6 in, 7 in

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

The answer is 70.8

Step-by-step explanation:

You do 7x3 times 2 and then 3x2.6 and then 7x3 again. You add them all up and get 70.8

21 + 21 + 3.9 + 3.9 + 21 = 70.8

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Can some help ...:.....0
frozen [14]

Answer:

-4

Step-by-step explanation:

Two legs of the triangle are congruent as shown by the tick marks. This means that this is an isosceles triangle; in an isosceles triangle, the two base angles are also congruent. Which means <A and <B are congruent.

So to solve for x, set 28 and 10x+68 equal to each other.

28=10x+68

First, subtract 68 from both sides

-40=10x

Then, divide both sides by 10

-4=x

If you want to check your answer plug -4 back into the original equation.

28=10(-4)+68

28=-40+68

28=28, which is true, therefore -4 is correct.

7 0
3 years ago
How to find area and perimeter HELP
denis23 [38]
Area : height x width
perimeter : 2(length + width)
5 0
3 years ago
Read 2 more answers
Angle kl bisects angle vkw. Classify angle vkw if measure of angle lkw is 25°
Tanya [424]
 angle lkw  = 25 degree
thus, angle vkw = 2 x 25 = 50 degree

as the angle vkw is 50 degree, angle vkw can be classified as an acute angle
3 0
3 years ago
Could someone please help me!??
scZoUnD [109]

Answer:

Step-by-step explanation:

i think its 1

8 0
3 years ago
Use the quadratic formula to find the solution to the question <br> 3x^2-10x+5=0
nlexa [21]

Answer:

x_{1}  = \frac{5 + \sqrt{10} }{3}  and x_{2} = \frac{5 - \sqrt{10} }{3}

Step-by-step explanation:

3x^2-10x+5=0

x_{1} = \frac{10 + \sqrt{10^{2}-4*3*5 } }{2*3}                  x_{2} = \frac{10 - \sqrt{10^{2}-4*3*5 } }{2*3}

x_{1} = \frac{10 + \sqrt{100-60} }{6}                      x_{2} = \frac{10 - \sqrt{100-60} }{6}

x_{1} = \frac{10 + \sqrt{40} }{6}                            x_{2} = \frac{10 - \sqrt{40} }{6}

x_{1} = \frac{10 + 2\sqrt{10} }{6}  / 2                    x_{2} = \frac{10 - 2\sqrt{10} }{6}  / 2

x_{1}  = \frac{5 + \sqrt{10} }{3}                             x_{2} = \frac{5 - \sqrt{10} }{3}

3 0
3 years ago
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