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Greeley [361]
3 years ago
7

FILL IN THE BLANKS: The solution to a system of equations is where two

Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0
The answer should be the second option (intersect, elimination, parallel, infinite) hope this helps you
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Plz help I’ll give Brainly
MrRissso [65]

Answer:

[i] Area of Juan's garden:

Soln,

length(l)=16

width(w)=12

area(a)=?

Now,

a=l×w

=16×12

=192

[ii] Area of Matthew's garden:

Soln,

length(l)=18

width(w)=21

area(a)=?

Now,

a=l×w

=18×21

=378

So,the area ofJuan's garden=192

And

the area of Matthew's garden=378

7 0
3 years ago
The number of sides of two regular polygons are as 1:2 and their interior angles are as 2:3 .Find the number of sides in each po
Tom [10]

Answer look below

Step-by-step explanation:

Hope this helps

8 0
3 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Greeley [361]

Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

Sample 1: Compressed soil

X₁: penetrability of a plot with compressed soil.

n₁= 20 plots

X[bar]₁= 2.90

S₁= 0.14

Sample 2: Intermediate soil

X₂: penetrability of a plot with intermediate soil.

n₂= 20 (with outlier) n₂= 19 plots (without outlier)

X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)

S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)

Outlier: 4.26

Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

Parámeter of interest: μ₁-μ₂

Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

5 0
3 years ago
Please help, thank you so much! I'll give brainliest to the correct answer!
ratelena [41]

Answer:

2

Step-by-step explanation:

This is because the other ones were going to be spent on something else, but then they were spent on magazines or flowers.

5 0
3 years ago
Read 2 more answers
a store is having a sale in which all items are reduced 20%. Including tax, Jennifer pail $21 for a pair of shorts. If the sales
andrey2020 [161]

Answer:

$25.

Step-by-step explanation:

Let x be the original price of shorts.

We have been given that a store is having a sale in which all items are reduced 20%. The  sales tax is 5%.  

The price of shorts after 20% off will be:

\text{ Price of shorts after discount}=x-\frac{20}{100}x

\text{ Price of shorts after discount}=x-0.2x

\text{ Price of shorts after discount}=0.8x

Since tax is added after the discount, so the price of shorts after including the tax will be:

0.8x+(\frac{5}{100}\times 0.8x)

We are told that including tax, Jennifer paid $21 for a pair of shorts. So we can set an equation as:

0.8x+(\frac{5}{100}\times 0.8x)=21

Now let us solve for x.

0.8x+(0.05\times 0.8x)=21

0.8x+0.04x=21

0.84x=21

\frac{0.84x}{0.84}=\frac{21}{0.84}

x=\frac{21}{0.84}

x=25

Therefore, the original price of shorts was $25.

7 0
3 years ago
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