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2 years ago

Answer ASAP

Mathematics

1 answer:

Yuki888 [10]2 years ago

6 0

Answer:

D. None.

Step-by-step explanation:

Say the obtuse angle is 100 degrees. Since the sum of all angles in a triangle cannot be bigger than 180, it's not possible because 195 (100+95) is greater than 180 degrees. Hope this helps.

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-3(-4b - 7n) use n = 8 and b = 2

gogolik [260]

The answer for your problem is 192

7 0

3 years ago

Please help NO LINKS ( i will mark brainliest)

Arlecino [84]

Answer:

with what

Step-by-step explanation:

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3 years ago

Problem 5.A miner is trapped inside a mine and has access to 3 doors. The first door leads to a tunneland can take him to safety

Likurg_2 [28]

Answer:

Expected time is 15 hours for him to get to safety.

Step-by-step explanation:

We define X as the time that this miner would get to safety.

We define Y as the door he chooses initially.

P(Y= 1) = P(Y=2)=P(Y=3) = 1/3

We have E[X|Y=1] = 3

E[X|Y] = 5 hours + E[X}

E[X|Y] = 7 hours + E[X]

Then we have

E[X] = 1/3(3 + 5 + E[X] + 7 + E[X])

We cross multiply

3*E[X] = (15 + 2E[x])

3E[X] - 2E[X] = 15

E[X] = 15

So the time it would take to get him to safety is 15 hours

5 0

3 years ago

Find the volume of a right circular cone that has a height of 6.7 in and a base with a diameter of 8.8 in. Round your answer to

N76 [4]

Answer: 135.8

Step-by-step explanation:

the formula for this is πr²H/3

π4.4^2x6.7/3

407.5/3

135.8

4 0

3 years ago

The specifications for an electronic device state that it is to be operated in a room with relative humidity ℎ defined by |ℎ − 5

Nadya [2.5K]

Answer: $\Large\boxed{20 < h < 80}$

Step-by-step explanation:

Given inequality

$|h-50| < 30$

The goal of the question

To find the minimum and maximum of the relative humidities

For this question, we need to solve the inequality

Simplify the absolute value sign

$h-50 < 30$ or $h-50 > -30$

Add 50 on both sides

$h-50+50 < 30+50$ or $h-50+50 > -30+50$

$\Large\boxed{h < 80}$ or $\Large\boxed{h > 20}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

1 year ago