Answer:
B. Offering advice about how best to perform a standard procedure.
Explanation:
Helping others can be in different ways, be it helping out or by giving encouraging words or advice. But in all aspects of help, there is always a positive outcome if help is given in the right way and at the right time. And it is also how one person lifts another.
A scientist can help a colleague out by offering advice and telling the person how to best perform a standard procedure. This will help the colleague do better in the experiment and also help ensure that the right things are done and the efforts are successful. The other options are all negative in their 'approach' which will only hinder the colleague in his/her works.
Thus, the correct answer is option B.
The microscopic observations of cells form the basis of the cell theory and the idea that all living things are composed of cells; cells are the structural and functional unit of living things.
False
Darker skin
Good luck
Answer:
1. Meiosis 1.
2. Meiosis 2.
3. End.
4A. The chromosome theory of inheritance states that chromosomes are the main carriers of the genetic factors responsible for inheritance.
B. Body cells have two sets of chromosomes while sex cells have one set. Therefore, when two sex cells meet, they form an embryo with two copies of each chromosomes thereby producing a body cell with the exact number of chromosomes. In essence, meiosis maintains the right number of chromosomes of body cells by creating half the number of chromosomes of sex cells.
C. Meiosis.
Explanation:
The likelihood that the first two offspring of the cross will have congenital analgesia would be 1/16
<h2>Autosomal Recessive Traits</h2>
For autosomal recessive traits, two recessive alleles are needed for the trait to manifest while one recessive allele means heterozygosity.
In this case, let us assume that congenital analgesia is represented by the allele b; heterozygous individuals will, thus, be Bb.
Bb x Bb
BB Bb Bb bb
Probability of producing unaffected offspring = 3/4
Probability of producing affected offspring = 1/4
Likelihood of the first two offspring having congenital analgesia = probability of first having congenital analgesia and the second having congenital analgesia
= 1/4 x 1/4
= 1/16
More on genetical probabilities can be found here: brainly.com/question/851793?referrer=searchResults
