There are many ways to solve number 5 as it is just an reduce/enlargement of equidistant fractions
The first method that came up to my mind is just dividing denominators.
For A) you can do 72 divided by 18 which would give you 4. Then you can divide the given numerator with the answer you got from dividing the denominators. This would be 8 divided by 4 which would give you two. This means that 2/18 is equal to 8/72. You can check by simplifying the fraction. Both 2/18 and 8/72 equal 9 when simplified, therefore correct.
You can use this method for b, either use a calculator because of the decimals or just remove the decimals and replace them later. Make sure when you use this method, you are always dividing the bigger number. So in B you would do 40.3 divided by 12.4
Answer:
A
Step-by-step explanation:
y=4x+6
y=6-4x
y=12
y=4x+6
12=4x+6
12-6=4x
6/4=4x/4
x=3/2
Answer: you can rent the kayak for 5.3 hours
Step-by-step explanation:
Total amount of money that you have to spend at the beach is 50.
A kayak cost 5 per hour to rent. This means that if you rent the Kayak for X hours, the amount that you will spend would be 5×x = 5x. I buy lunch for 8.50. I want to save 15 for food later. This means that total amount of money spent is the sum of money spent in renting the kayak and buying of lunch.
Total amount spent = 5x + 8.50
Total amount spent + Total amount that you want to save = Total amount of money that you have to spend at the beach. Therefore
5x + 8.50 + 15 = 50 - 15 - 8.5 = 26.5
x = 26.5/5 = 5.3
the answer is the litter B
Answer:
156.25 grams
Step-by-step explanation:
Well, for starters we know that the substance decays by 2% each day and its been decaying for 34 days. Therefore, the substance has decayed by 68%
34 x 2 = 68
Hence, 50 grams is 32% because the substance has already decayed by 68%
100 - 68 = 32
So now we know 50 grams is 32%. Now we need to find how much 100% is.
50 - 32%
X - 100%
We cross multiply.
50 x 100 = 5000
And divide.
5000 / 32 = 156.25
Thus, in the beginning, there were 156.25 grams in the substance.
Hope this helps! :)