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3 years ago

Simplify the ratio 49:35

Mathematics

2 answers:

Andreyy893 years ago

7 0

7:5 There's your answer :)

ladessa [460]3 years ago

6 0

9/5 ...,.....,..... that us the answer

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1.1

solniwko [45]

Answer:

$Cost = 112.266$ cent/km

Step-by-step explanation:

Given

$Unit\ cost = R17.82/litre$

$Rate = 6.3litre/100km$

Required

The fuel cost in $cent\ per\ km$

This is calculated using:

$Cost = Unit\ cost * Rate$

$Cost = R17.82/litre * 6.3litre/100km$

$Cost = R17.82 * 6.3/100km$

$Cost = R1.12266/km$

Multiply by $100$ to get the cost in cents

$Cost = 1.12266 * 100$ cent/km

$Cost = 112.266$ cent/km

6 0

3 years ago

A 12-foot ladder leans against the wall; the base of the ladder is 2 feet away from the wall.To the nearest tenth of a foot, how

ludmilkaskok [199]

<h3>The ladder will reach a height of 11.8 feet up the wall</h3>

Solution:

The ladder, wall and base of the ladder from wall forms a right angled triangle

Length of ladder forms the hypotenuse

Length of ladder = 12 foot

base of the ladder from wall = 2 feet

To find: height of wall

By pythagoras theorem.

$c^2 = a^2+b^2$

Where,

"c" is the Length of ladder

"a" is the base of the ladder from wall

"b" is the height of wall

Substituting the values,

$12^2 = 2^2+b^2\\\\144 = 4 + b^2\\\\b^2 = 140\\\\b = \pm 11.832 \\\\Ignore\ negative\ value\\\\b \approx 11.8$

Thus, the ladder will reach a height of 11.8 feet on wall

4 0

3 years ago

Paula purchased adult and child tickets for the carnival. Tickets cost $19.95 for each adult and $9.95 for each child. Let x rep

katovenus [111]

Answer:

19.95x+9.95y= Total cost

Step-by-step explanation:

5 0

3 years ago

Which of the following can not be used on a matrix when solving a system of equations

Aneli [31]

add a constant to a row right?

3 0

4 years ago

What is the equation of the line that is perpendicular to the given line and passes though the point (3,0)? ......What is the an

Stolb23 [73]

Answer: The correct option is (D) $5x-3y=15.$

Step-by-step explanation: We are given to find the equation of a line that is perpendicular to the graphed line and passes through the point (3, 0).

From the graph, we note that

the graphed line passes through the points (2, -1) and (-3, 2).

The SLOPE of a straight line passing through the points (a, b) and (c, d) is given by

$m=\dfrac{d-b}{c-a}.$

So, the slope of the graphed line is

$m=\dfrac{2-(-1)}{-3-2}\\\\\Rightarrow m=-\dfrac{3}{5}.$

We know that the product of the slopes of two perpendicular lines is -1. So, if m' is the slope of a line perpendicular to the graphed line, then

$m\times m'=-1\\\\\Rightarrow -\dfrac{3}{5}\times m'=-1\\\\\Rightarrow m'=\dfrac{5}{3}.$

Since the line with slope m' passes through the point (3, 0), so its equation will be

$y-0=m'(x-3)\\\\\\\Rightarrow y=\dfrac{5}{3}(x-3)\\\\\Rightarrow 3y=5x-15\\\\\Rightarrow 5x-3y=15.$

Thus, the required equation of the perpendicular line is $5x-3y=15.$

Option (D) is CORRECT.

8 0

3 years ago