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xz_007 [3.2K]
3 years ago
14

A 12-foot ladder leans against the wall; the base of the ladder is 2 feet away from the wall.To the nearest tenth of a foot, how

far up the wall does the ladder reach?
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0
<h3>The ladder will reach a height of 11.8 feet up the wall</h3>

<em><u>Solution:</u></em>

The ladder, wall and base of the ladder from wall forms a right angled triangle

Length of ladder forms the hypotenuse

Length of ladder = 12 foot

base of the ladder from wall = 2 feet

<em><u>To find: height of wall</u></em>

By pythagoras theorem.

c^2 = a^2+b^2

Where,

"c" is the Length of ladder

"a" is the base of the ladder from wall

"b" is the height of wall

Substituting the values,

12^2 = 2^2+b^2\\\\144 = 4 + b^2\\\\b^2 = 140\\\\b = \pm 11.832 \\\\Ignore\ negative\ value\\\\b \approx 11.8

Thus, the ladder will reach a height of 11.8 feet on wall

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