All categories

2 years ago

Find the missing number 3+=5?

Mathematics

2 answers:

madam [21]2 years ago

6 0

2.
Explanation
2+3=5
5-3=2

GrogVix [38]2 years ago

6 0

Answer:

Step-by-step explanation:

We can view this problem as 5-3=?.

5-3=2

So the missing number is 2.

You might be interested in

Question 8 the price of a cup of coffee was $2.55 yesterday. today, the price fell to $2.40 . find the percentage decrease. roun

Alex787 [66]

The answer would be 5.9%

3 0

3 years ago

The multiplicative inverse of -7/8 is

suter [353]

7/8 is a answer of this question

3 0

3 years ago

A test has 20 true/false questions. What is the probability that a student passes the test if they guess the answers? Passing me

Minchanka [31]

Using the binomial distribution, it is found that:

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

For each question, there are only two possible outcomes, either the guess is correct, or it is not. The guess on a question is independent of any other question, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 20 questions, hence $n = 20$ .

Each question has 2 options, one of which is correct, hence $p = \frac{1}{2} = 0.5$

The probability is:

$P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 15) = C_{20,15}.(0.5)^{15}.(0.5)^{5} = 0.0148$

$P(X = 16) = C_{20,16}.(0.5)^{16}.(0.5)^{4} = 0.0046$

$P(X = 17) = C_{20,17}.(0.5)^{17}.(0.5)^{3} = 0.0011$

$P(X = 18) = C_{20,18}.(0.5)^{18}.(0.5)^{2} = 0.0002$

$P(X = 16) = C_{20,19}.(0.5)^{19}.(0.5)^{1} = 0$

$P(X = 17) = C_{20,20}.(0.5)^{20}.(0.5)^{0} = 0$

Then:

$P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0148 + 0.0046 + 0.0011 + 0.0002 + 0 + 0 = 0.0207$

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

You can learn more about the binomial distribution at brainly.com/question/24863377

6 0

2 years ago

A standard deck of playing cards has 13 cards in each of four suits: hearts, clubs, diamonds, and spades. Two cards are chosen f

Aloiza [94]

Answer:

Probability of choosing one club and one spade = 0.6025

Step-by-step explanation:

Total number of cards= 52 cards

For the first event

Probability of choosing a club

Toatal club = 13 cards

Probability of choosing a club

= 13/52

Probability of choosing a club

= 1/4

Probability of choosing a club

=0.25

For the second event

Probability of choosing a spade

Toatal spade = 13 cards

Probability of choosing a spade

= 13/52

Probability of choosing spadep

= 1/4

Probability of choosing a spade = 0.25

Probability of both = 0.25*0.25

Probability of both = 0.6025

5 0

2 years ago

(Will mark brainest)If it rains tomorrow the probability is 0.6 that James will practice piano. if it doesn't rain tomorrow ther

sergiy2304 [10]

Answer:

0.64

Step-by-step explanation:

P(J / R) = P (J and R) / P(R)

0.8 = P (J and R) / 0.6

P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining]

P(J / NR) = P (J and NR) / P(NR)

0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4

P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining]

Hence;

Probability of John practicing regardless of weather condition is

P(John Practicing) = 0.48 + 0.16 = 0.64

HOPE THIS HELPED!!!

7 0

3 years ago