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Crazy boy [7]
2 years ago
9

L Factor the greatest common factor (GCF) from each polynomial. 10n^3 - 35n^2+25n​

Mathematics
1 answer:
Maru [420]2 years ago
4 0

Answer:

5n(2n^2-7n+5)

Step-by-step explanation:

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Rashad is having a picnic for 62 guests. He plans to serve each guest at least one hamburger. If each package, p, contains eight
Stels [109]

Answer:

Are you in connections academy to X3

I personally got 8p(the more than or equal to sign) 62

i could be wrong cause i dont know it either

8 0
4 years ago
Last question helo me pls
Yuri [45]
I hope this helps you

3 0
4 years ago
Someone please tell if this is right!
sertanlavr [38]

Answer:

Step-by-step explanation:

-4x , for the top right box, the rest are good

4 0
2 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
Which of the following expression has the greatest value: -3+-4-(-2),-3-(-4)-(-2),-3+-4-2,-3-(-4)-2
AleksAgata [21]
The third one
U solve from left to right and when two negatives are next to each other it turns to a plus.
6 0
3 years ago
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