Well, first off, you see how all the answers say a fraction, then pi? that means that you don't calculate pi into your answer.
But lets see. The radius is 4. V=(4/3)pi*r^2
V=(4/3)pi*4^2
V=(4/3)pi*16
V=(4/3)*16*pi
V=(4/3)*(16/1)*pi
V=(4*16)/(3*1)*pi
V=64/3*pi
so the answer is (B) 64/3pi units cubed.
3y^-4 × (2y^-4) = 6y^-8
= 6/1/y^8
= 6/y^8
.................................................
1) When x^1 multiply with x^2, 1 will add to 2 and become 3
= x^3
2) y^-1 = 1/y
3^-2 = 1/3^2 = 1/9
5^-2 = 1/5^2 = 1/25
Answer:78.5
Step-by-step explanation:
Because the diameter is always going to be twice the radius and area equal pi which is 3.14
Part A
For Todd's class, we have this given info:
- mu = 70.6 = population mean of math scores
- sigma = 11.9 = population standard deviation of math scores
Compute the z score for x = 74.6
z = (x-mu)/sigma
z = (74.6 - 70.6)/(11.9)
z = 0.34 approximately
Side note: Convention usually has z scores rounded to two decimal places. If your teacher instructs otherwise, then go with those instructions of course.
<h3>Answer: 0.34</h3>
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Part B
For Garret's English class, we have:
Compute the z score for x = 68.8
z = (x-mu)/sigma
z = (68.8 - 63.7)/(8.6)
z = 0.59 approximately
<h3>Answer: 0.59</h3>
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Part C
Garret has the higher z score, which means that Garret did relatively better to his classmates compared to Todd's performance (in relation to his classmates). The z score is the distance, in units of standard deviation, the score is from the mean. Positive z values are above the mean, while negative z values are below the mean.
<h3>Answer: Garret did relatively better</h3>
This looks like an exercise that's building toward the idea of a derivative.
These calculations are done best with a calculator, but here's how the first interval is used:
Average velocity = (position at 2 - position at 1) / (2 - 1) It's really distance divided by time!
Position at t = 2:
Position at t = 1:
So over the interval [1, 2] the average velocity is
I used a spreadsheet to calculate the average velocity over the other intervals and a couple of shorter ones, too. (See attached image.)
As these intervals get shorter (the right endpoint is approaching 1), the average velocity gets closer and closer to the instantaneous velocity. An estimate would be -12.6.