All categories

3 years ago

[geometry] i got 267.94 but how do i answer that in fraction?

Mathematics

1 answer:

Firlakuza [10]3 years ago

8 0

Well, first off, you see how all the answers say a fraction, then pi? that means that you don't calculate pi into your answer.
But lets see. The radius is 4. V=(4/3)pi*r^2
V=(4/3)pi*4^2
V=(4/3)pi*16
V=(4/3)*16*pi
V=(4/3)*(16/1)*pi
V=(4*16)/(3*1)*pi
V=64/3*pi
so the answer is (B) 64/3pi units cubed.

You might be interested in

Which describes the graph of y = (x - 5)2 - 4?

Schach [20]

Answer:

A. Opens up with a vertex at (5,-4)

Step-by-step explanation:

Apex

4 0

2 years ago

A woman prospecting for successful business travels 16km from a point P to a point Q on a bearing of 065°. She then travels to p

SashulF [63]

Answer:

The distance PR is 21.6 Km

Step-by-step explanation:

Please find the attached document for explanation.

Also, I applied Cosine rule to determine the distance PR, since i have an angle (Q) in between two given sides of the triangle.

8 0

2 years ago

Find the 7th term in the sequence -10,-6,-2,2...

jeyben [28]

1st term = -10

2nd term = -6

3rd term = -2

4th term = 2

5th term = 6

6th term = 10

7th term = 14

The reason how I got 14 for the 7th term is because, i added 4 to each term.

Hope this helps!

3 0

3 years ago

Read 2 more answers

Pleeeeeeeese help me I will mark you as brainliest

laiz [17]

$\orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTION}}}}}}}$

FIND THE NUMBER THAT MAKE EQUIVALENT FRACTION.

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

$\red{solved} \\ \frac{4}{ \cancel{5}} = \frac{x}{ \cancel{40}^{ \: \: \: \tiny{8}} } \\ 8 \times 4 = x \\ 32 = x$

$\blue{Part - 1} \\ \frac{4}{ \cancel{6}} = \frac{x}{ \cancel{24}^{ \: \: \: \tiny{4}} } \\ 4\times 4 = x \\ 16 = x$

$\green{Part - 2} \\ \frac{1}{ 2} = \frac{6}{ x } \\ 6 \times 2 = x \\ 12 = x$

SOLVE LIKE THIS FOR ALL

PART - 3 --> 12

PART - 4--> 40

PART - 5 --> 6

PART - 6--> 4

PART - 7 --> 54

PART - 8 --> 12

PART - 9--> 36

PART - 10 --> 28

PART - 11--> 20

PART - 12 --> 28

PART - 13 --> 16

PART - 14 --> 20

PART - 15 --> 12

PART - 16 --> 6

PART - 17 --> 32

PART - 18--> 30

PART - 19 --> 27

PART - 20 --> 36

6 0

3 years ago

Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$