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Marysya12 [62]
2 years ago
10

SOLVE 5( 2y-1)-2(2-y)+3(2y+9)=0

Mathematics
2 answers:
Nikolay [14]2 years ago
8 0

Answer:

y = -1

Step-by-step explanation:

5(2y−1)−2(2−y)+3(2y+9)=0

Step 1: Simplify both sides of the equation.

5(2y−1)−2(2−y)+3(2y+9)=0

(5)(2y)+(5)(−1)+(−2)(2)+(−2)(−y)+(3)(2y)+(3)(9)=0(Distribute)

10y+−5+−4+2y+6y+27=0

(10y+2y+6y)+(−5+−4+27)=0(Combine Like Terms)

18y+18=0

18y+18=0

Step 2: Subtract 18 from both sides.

18y+18−18=0−18

18y=−18

Step 3: Divide both sides by 18.

18y/18 = -18/18

Answer: y=−1

USPshnik [31]2 years ago
5 0
Open bracket
10y-5-4+2y+6y+27=0
Add up all y values and numbers
18y+18=0
Take y values to the opposite side
18y=-18
y=-1
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Part A: Factor x2y2 + 6xy2 + 8y2. Show your work. (4 points) Part B: Factor x2 + 8x + 16. Show your work. (3 points) Part C: Fac
skad [1K]

Answer:

Part A : y²(x + 2)(x + 4)

Part B: (x + 4) (x + 4)

Part C: (x + 4) (x - 4)

Step-by-step explanation:

Part A: Factor x²y²+ 6xy²+ 8y²

x²y²+ 6xy²+ 8y²

y² is very common across the quadratic equation , hence

= y² (x² + 6x + 8)

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Part B: Factor x² + 8x + 16

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= (x² + 4x) - (4x - 16)

= x (x + 4) - 4(x + 4)

= (x + 4) (x - 4)

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