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Advocard [28]
2 years ago
5

Find the equation of the circle whose diameter is the chord x + y = 3 of the circle x2 + y2 - 2x - 3 = 0​

Mathematics
1 answer:
liubo4ka [24]2 years ago
8 0

Answer:

x2 + y2 − x + 3y + 2 = 0.... . [3]

Step-by-step explanation:

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The 10-second barrier in the 100-meter dash was first broken in the 1968 Olympics, when the winning time was 9.95 seconds. A gym
Gemiola [76]

Answer:

4.75 seconds

Step-by-step explanation:

14.7 - 9.95

5 0
2 years ago
Read 2 more answers
If a half gallon milk costs $1.24, what is the cost per pint?
PIT_PIT [208]

Hello! The answer is: $0.31


7 0
3 years ago
Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?
Artemon [7]

Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

\sqrt{(x+3)^2+(y-3)^2}

and the distance between (x, y) and the directrix y = 7 is

\sqrt{(y-7)^2}.

On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

6 0
3 years ago
Which statement comparing these measures is true? A microgram is 1,000 times greater than a milligram.
ololo11 [35]
The statement is false.

The statement below is true.
A milligram is 1000 times greater than a microgram.
3 0
3 years ago
The position of an object moving along a straight line for
NikAS [45]

Answer:

at 2/3 seconds

Step-by-step explanation:

S1(t) = t³ + 2

Average speed, dS1/dt = 3t²

S2(t) = t²

Average speed, dS2/dt = 2t

The distance between the objects is

dS1/dt - dS2/dt

= 3t² - 2t

The time the distance between the two object is at minimum is when the distance is 0

That is, when

3t² - 2t = 0

t(3t - 2) = 0

t = 0 or 3t - 2 = 0

t = 0 or t = 2/3

3 0
3 years ago
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