Transitive property of equality is stated as:
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If a is equal to b and b is equal to x, then a is equal to c.
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An example is:
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3x -5 = 2y +3
</span><span>2y + 3 = 6z -1</span><span>
therefore,
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3x-5 = 6z-1</span><span>
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Just set them equal to each other
2x-2= x+3
2x-5=x
-5= -x
X=5
Hope it helps
Answer:
f(x) has three real roots and two imaginary roots.
Step-by-step explanation:
Given that three roots of a fifth degree polynomial function f(x) are -2,2 and (4+i).
Now we need to find about which of the given statements describes the number and nature of all roots for this function.
We know that imaginary roots always occur in conjugate pairs.
So if (4+i) is root then (4-i) must also be the root.
So now we have total 4 roots
-2, 2, (4+i) and (4-i).
Degree of the polynomial is 5 so that means 1 root is still remaining. It can't be imaginary as that must be in pairs
So that means 5th root is real.
Hence correct choice is :
f(x) has three real roots and two imaginary roots.
