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Colt1911 [192]
3 years ago
6

Rectangle JKLM undergoes a sequence of transformations, resulting in rectangle J’K’L’M’. The length of side K’L’ is 6 units. The

coordinates of vertex K’ are (-3, 2), and the coordinates of vertex M’ are (3, -2). Describe a sequence of transformations to rectangle JKLM that would result in rectangle J’K’L’M’.
Mathematics
2 answers:
rewona [7]3 years ago
8 0
J f k is the answer
harina [27]3 years ago
3 0

Answer:

J,F,K

Step-by-step explanation:

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The correct answers are :

(5x)² ≥ 46

x² + 5x ≤ 46

5x² > 46

<h3>What is Inequalities?</h3>

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Here, Suppose number is x

1)  The square of the product of 5 and a number is not less than 46.

Step 1

Product of 5

5x

Step 2

Square of product of 5

(5x)²

Step 3

A number is not less than 46

(5x)² ≥ 46

2)  The sum of square of a number and five times that number is not more than 46

Step 1

Square of a number

x²

Step 2

Five times that number

5x

Step 3

The sum = x² + 5x

Step 4

Is not more than 46

x² + 5x ≤ 46

3)  The product of 5 and the square of a number is greater than 46

Step 1

The square of a number

x²

Step 2

The product of 5

5x²

Step 3

Is greater than 46

5x² > 46

Thus, The correct answers are :

(5x)² ≥ 46

x² + 5x ≤ 46

5x² > 46

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

3 0
2 years ago
7. A vase 25 cm tall is positioned on a bench near a wall as shown. The shape of the vase follows the curve y = (x - 10)^2, wher
Kitty [74]

Answer:

Step-by-step explanation:

the base of the vase will be where the vase touches the x-axis, that is 10 cm, therefore, the base is 10 cm from the wall

:

b) 25 = x^2 -20x +100, we solve for x to find the closest distance since as we move up the vase the distance to the wall gets closer(assume the y-axis is the wall), then

x^2 -20x +75 = 0  (x-15) * (x-5) = 0

x = 15 and x = 5

we reject x = 15

the shortest distance from the top of the vase to the wall is 5 cm

:

c) this is a left shift of the equation y = (x-10)^2

from b) we know that the left shift is 5 cm

10 - 5 = 5 cm from the wall to the base

:

d) y = (x-10+5)^2

y = (x-5)^2    

4 0
2 years ago
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