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3 years ago

A school sold tickets to a musical. The school received $6.50 per ticket sold.

Mathematics

2 answers:

uranmaximum [27]3 years ago

7 0

Options 1 & 3 would be correct

Kamila [148]3 years ago

3 0

Answer: m=$6.50t AND t$6.50=m

Step-by-step explanation:

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I need help plz help me!!!!

AlexFokin [52]

Answer:

5/8 =)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The water in a reservoir decreased by 47% during a drought. Before the drought, the reservoir held 44,580 acre ft (AF) of water.

RSB [31]

44,580 x 47 %

44,580 x .47 = 20,952.6

So, the water decreased 20,952.6 ft

If you want the water level after the drought just subtract.

44,580 - 20,952.6 = 23,627.4 ft

Hope this helps. :)

5 0

3 years ago

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

2 years ago

The stadium owner is considering an offer from Reliable Tools to change the name to Reliable Stadium. The company is offering to

defon

The answer is probably 590,000 because isn't it subtraction

6 0

3 years ago

Read 2 more answers

In 1950 the number of retirees was approximately 150 per thousand people aged 20-64. In 1990 this number rose to approximately 2

serg [7]

Answer: 233 people per thousand

Step-by-step explanation:

Using extrapolation method,

if 150/k in 1950,

200/k in 1990,

275/k in 2020,

2003 lies in between 1990 and 2020. So, you extrapolate the values of 200/k and 275/k for the years respectively.

Therefore,

(2003 - 1990)/(2020 - 2003) = (x - 200)/(275 - x)

Where x is the number of retirees per thousand for 2003

Making x the subject of relation in the above equation.

Cross multiply the equation above;

(2003 - 1990)(275-x) = (2020 - 2003)(x - 200)

13(275 - x) = 17(x-200)

3575 - 13x = 17x - 3400

Collect the like terms

3575+3400 = 17x + 13x

30x = 6975

x = 6975/30

x = 232.5

x = 233 people per thousand to the nearest integer

6 0

3 years ago