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2 years ago

How much more intense is an 8. 5 earthquake than a 5. 5

Mathematics

1 answer:

AleksandrR [38]2 years ago

6 0

Answer:

it is more intense by 3.0

Step-by-step explanation:

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5c+ 3 < 28 or -4c-2< 14 for c.

sweet-ann [11.9K]

Answer:

c<5, and c>-4.

<u>Steps used for answers:</u>

5c+3<28 =

1. Subtract 3 from both sides.

5c<28-3

2. Simplify 28-3 to 25.

5c<25

3. Divide both sides by 5.

c<25/5

4. Simplify 25/5 to 5.

c<5

-----------------------

-4c-2<14 =

1. Add 2 to both sides.

-4c<14+2

2. Simplify 14+2 to 16.

-4c<16

3. Divide both sides by -4.

c>-16/4

4. Simplify 16/4 to 4.

c>−4

<u>Done by NeighborhoodDealer</u>

3 0

3 years ago

Read 2 more answers

Add 3/4+(−2 1/2) using the number line.

Neko [114]

Answer:

-1 3/4

Step-by-step explanation:

6 0

3 years ago

Are either of these linear?

sesenic [268]

The 2nd one is linear

7 0

3 years ago

I need help plsssss...........

ch4aika [34]

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

system of linear equation
PEMDAS

<h3>let's solve:</h3>

since y is equal to both equation therefore we can substitute the value of y into the other equation

$\sf substitute \: the \: value \: of \: y : \\ \sf - x + 2 = 3x - 4$
$\sf add \: x \: to \: both \: sides : \\ \sf - x + x + 2 = 3x + x - 4 \\ \sf 4x - 4 = 2$
$\sf add \: 4 \: to \: both \: sides : \\ \sf xx - 4 + 4 = 2 + 4 \\ 4x = 6$
$\sf divide \: both \: sides \: by \: 4 : \\ \frac{4x}{4} = \frac{6}{4} \\ x = \frac{3}{2}$