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Leokris [45]
3 years ago
8

How much more intense is an 8. 5 earthquake than a 5. 5

Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0

Answer:

it is more intense by 3.0

Step-by-step explanation:

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Please help me :(<br> this is really hard
avanturin [10]

Answer:

h ≈ 7.9 cm

Step-by-step explanation:

Using the sine ratio in the right triangle

sin26° = \frac{opposite}{hypotenuse} = \frac{h}{18} ( multiply both sides by 18 )

18 × sin26° = h , then

h ≈ 7.9 cm ( to 1 dec. place )

8 0
3 years ago
Read 2 more answers
Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8
mojhsa [17]
{ x + 3 y = 7      * ( - 2)
 2 x + 4 y = 8 

{ - 2 x - 6 y = - 14
    2 x + 4 y = 8
_______________
             -2 y =  - 6   * ( -1)

 2 y = 6

y = 6 / 2

y = 3

For x :

2 x + 4 y = 8

2 x + 4 * ( 3) = 8

2 x + 12 = 8

2 x = 8 - 12

2 x = - 4

x = - 4 / 2

x = - 2

Solution:   x = -2    and  y = 3 

hope this helps!

8 0
3 years ago
Trick question<br> whats 50 divided by half plus 10
hoa [83]
50:\frac{1}{2}+10=50\cdot\frac{2}{1}+10=50\cdot2+10=100+10=\boxed{110}
5 0
3 years ago
What is the length, in centimeters (cm), of y?
Andre45 [30]

Answer:

should be 6

Step-by-step explanation:

Pythagorean Theorum was used.

6 0
3 years ago
Read 2 more answers
How do I approximate a square root
Roman55 [17]
The calculus approach is to use Newtons Method:
x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}
where 
f(x) = x^2 - a
Start with initial guess of "a".
After 4 or 5 iterations, you should get a close approximation to \sqrt{a}
...............

If you wanted a non-calculus approach, I would suggest divide and conquer.
First determine which 2 integers the sqrt lies in between by perfect squares.
m^2\ \textless \ a \ \textless \ n^2
Then use midpoint \frac{m+n}{2} for next guess, if 
(\frac{m+n}{2})^2 \ \textless \  a
then repeat with "m" = midpoint. Otherwise repeat with "n" = midpoint.
Continue until you have a good approximation, about 6-8 decimal points.
4 0
4 years ago
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