Answer:
a F
Step-by-step explanation:
Normally when converting to scientific notation, I would count how many digits I have to move the decimal dot to get it in between the number, in this case, 36.
If you start shifting the decimal dot to the right and count one every time you shift one digit and go all the way to between 3 and 6, you would count to 5. Since you are shifting to the right, the power of the 10 should be negative. Thus, the answer should be 3.6 × 10
which is F.
Answer:
1222
Step-by-step explanation:
312/12 = 26
So, you have to multiply y (47) by 26
This will get you 1222
Answer:
First option is correct answer.
Step-by-step explanation:
Area = 4x - 10
Perimeter = x + 8
The correct option is: Option (B)

Explanation:
First thing is that the difference between each number in the series with the next number is 5. It means it must be the multiple of 5. There are two options that contain multiples of 5: Option B and Option D. Now in the option D, the upper limit is 6. If we put 6 in the expression: 5(6)-2, the last term would be 28. However in the series given in the question, the last term is 33. Hence 5(7) - 2 = 35 - 2 = 33 which is Option B.
When i=1: 5(1)-2 = 3
When i=2: 5(2)-2 = 8
When i=3: 5(3)-2 = 13
.
.
When i=7: 5(7)-2 = 35-2 = 33
Hence the correct option is (B).
Answer:
Step-by-step explanation:
I've enclosed a graph to show you that there is one solution.
-4x + 3y = - 12
<u>- 2x + 3y = - 18</u><em><u> </u></em><em> </em>Subtract
-2x = 6 Divide by - 2
-2x/-2 = 6/-2
x = - 3
- 4x + 3y = - 12
-4(-3) + 3y = - 12
12 + 3y = - 12
3y = - 12 - 12
3y = - 24
3y/3 = - 24/3
y = - 8
Which is exactly what the graph shows.
You can tell immediately that this has 1 or more solutions just by looking at the number in front of x and y in each each equation.
It's always a good idea to graph a question like this one. Desmos is a pretty good tool to use if you don't have a graphing calculator.
The y's are the same so you are 1/2 way home in saying what you did.
The x's are different so that means you have at least 1 solution.