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2 years ago

Graph it y=1/2x+8\\5x+2y=-8[/tex]

Mathematics

2 answers:

SSSSS [86.1K]2 years ago

8 0

Answer: ITS IS THIS or that i dont know what you mean.

Step-by-step explanation: Is this what you're looking for? if you were paying attention you would've KNOWN SO NExt time PAY ATTENTION BUT GOOD LUCK

Ymorist [56]2 years ago

3 0

Answer:

(0,8), (8,-1)

Step-by-step explanation:

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Will give brainliest Of the following sets, which numbers in {1, 2, 3, 4, 5} make the inequality 5x + 2 > 12 true? (5 points)

Radda [10]

Answer:

x = 3, 4, 5

Step-by-step explanation:

Solving the inequality

5x + 2 > 12 ( subtract 2 from both sides )

5x > 10 ( divide both sides by 5 )

x > 2

Thus the only values from the given set which make the inequality true are

x = 3, 4, 5

4 0

3 years ago

Read 2 more answers

A (0, 2) and B (6,6) are points on the straight line ABCD.

elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ , the distance is denoted by: $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ . Let's find the distance between A and B:

d = $\sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}$

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = $\sqrt{(6-a)^2+(6-b)^2}$

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

208 = (6 - a)² + (6 - b)²

208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

0 = 13/9a² - 52/3a - 156

13a² - 156a - 1404 = 0

a² - 12a - 108 = 0

(a + 6)(a - 18) = 0

a = -6 or a = 18

We know a can't be negative so a = 18. Plug this back in to find b:

b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0