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alexandr1967 [171]
3 years ago
12

Make 24 with the numbers below : 5, 10, .5, 1

Mathematics
1 answer:
Bond [772]3 years ago
7 0

Answer:

0.5(5 × 10) - 1

Step-by-step explanation:

((5 × 10) × 0.5) - 1

((50) × 0.5) - 1

25 - 1

24

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Which expression has an estimated product of 60?
Inessa05 [86]

Answer:

(13.2)(4.5)

Step-by-step explanation:

This is correct because you know that you could round one up, and one down. You know that 12*5 = 60, so you could estimate that these would have a product of 60.

6 0
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Evaluate 144 - abc if a = 3, b = 4, and c = 12.
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Answer is c=12 on edge 2020
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How do you solve: 5In3-2In9
eimsori [14]

Answer: uhm is this a SAT

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3 years ago
Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/22 , 2 1/4 ) and (−2
Nana76 [90]

Answer: k=18\dfrac{8}{11}.

Step-by-step explanation:

If a line passing through two points, then

Slope=\dfrac{y_2-y_1}{x_2-x_1}

Endpoints of segment MN have coordinates (0, 0) and (5, 1).

Slope of MN =\dfrac{1-0}{5-0}=\dfrac{1}{5}

The endpoints of segment AB have coordinates \left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right) and  \left(-2\dfrac{1}{4} , k\right).

A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)

B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right).

Slope of AB =\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}

=\dfrac{\frac{4k-9}{4}}{\frac{-99-46}{44}}

=\dfrac{4k-9}{4}\times \dfrac{44}{-145}

=4k-9\times \dfrac{11}{-145}

=\dfrac{44k-99}{-145}

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

\dfrac{1}{5}\times \dfrac{44k-99}{-145}=-1

\dfrac{44k-99}{-725}=-1

44k-99=725

44k=725+99

k=\dfrac{824}{44}

k=\dfrac{206}{11}

k=18\dfrac{8}{11}

Therefore, the value of k is k=18\dfrac{8}{11}.

8 0
4 years ago
Read 2 more answers
Which corresponds to the perimeter of triangle ABC?
____ [38]

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

A (-5 , -1)

B (-2, 3)

C (6, -3)

Perimeter = ?

Formula

d = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }

distance AB      d = \sqrt{(-2 + 5)^{2} + (3 + 1)^{2} }

                         d = \sqrt{(3)^{2} + (4)^{2} }

                         d = \sqrt{(9 + (16) }

                                 d = \sqrt{25}

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Distance BC    d = \sqrt{(-3 - 3)^{2} + (6 + 2)^{2} }

                         d = \sqrt{(-6)^{2} + (8)^{2} }

                         d = \sqrt{36 + 64}                    

                         d = \sqrt{100}

                                d = 10

Distance AC     d = \sqrt{(-3 + 1)^{2} + (6 + 5)^{2} }

                         d = \sqrt{(-2)^{2} + (11)^{2} }

                         d = \sqrt{4 + 121}

                         d = \sqrt{125}

                                d = 11.2

Perimeter = 5 + 10 + 11.2

                = 15 + \sqrt{125}

4 0
4 years ago
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