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ch4aika [34]
2 years ago
7

Plss help I need it ASAPnonsense=reported ​

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
7 0

pls mark brainliest

ans is 25 degree

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The ratio of the cost of a tennis racket ro tennis balls is 18:1. If a can of balls cost $5.35, what is the cost of the racket?
siniylev [52]

Multiply the ratio by $5.35

racket : balls = 18×$5.35 : 1×$5.35 = $96.30 : $5.35

The racket costs $96.30.

5 0
3 years ago
Identify the corresponding word problem given the equation: x = 10 × 200 A) Frank and ten workers are hired to harvest tomatoes
Sliva [168]
I think it is c hope it helps.
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Jerry has 6 candys he lost 2 how much does he have?
Aleksandr-060686 [28]

Answer:

Hello there!

Since he had 6 candies and lost two, all you have to do is subtract 2 from 6.

Therefore, Jerry only has 4 candies.

Hope this helps!!!

Step-by-step explanation:

5 0
3 years ago
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If roberto can build 1 house in 23 days, how many houses can he build in 207 days?
rusak2 [61]
He would be able to build 9 houses.

\frac{207}{23} = 9
3 0
3 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
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