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Morgarella [4.7K]
2 years ago
14

Hurry please!

Mathematics
1 answer:
Alexus [3.1K]2 years ago
3 0

Answer:

C. $8483

Step-by-step explanation:

To find the  coffee sales, we plug in the value of x as 34 into y = 60x + 6443.

  • y=60(34)+6443
  • y=2040+6443
  • y=8483

Therefore, the answer is C. $8483.00.

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Classify each sequence as arithmetic, geometric or neither
Karolina [17]

Answer:

Geometric sequence = ⁵/9, ⁵/3, 5, 15, 45. . .

Arithmetic sequence = 16, 11, 6, 1, -4 . . .

Step-by-step explanation:

A geometric sequence is a sequence of numbers, in which every number in the sequence after the first term is multiplied by a common ratio, which gives us the next term. The common ratio is the ratio of a term to the term before it.

On the other hand, an arithmetic sequence is a sequence of number have a common difference between each consecutive terms. This common difference is gotten by subtracting a term from the term before it.

Now let's examine each sequence given:

==>16, 11, 6, 1, -4 . . .

11 - 16 = -5

6 - 11 = -5

1 - 6 = -5

-4 - 1 = -5

This is an arithmetic sequence. The commons difference "-5" is the same

==>⁵/9, ⁵/3, 5, 15, 45. . .

⁵/3 ÷ ⁵/9 = ⁵/3 × ⁹/5 = ⁹/3 = 3

5 ÷ ⁵/3 = ⁵ × ⅗ = 3

15 ÷ 5 = 3

45 ÷ 15 = 3

The common ratio "3" is the same. This is a geometric sequence.

3 0
3 years ago
What is <br> 8 + 2 × 6 - 2^4
chubhunter [2.5K]

Answer:

4

Step-by-step explanation:

8+2=10

10x2=60

60-2^4=4

the value of 2^4 is 56

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3 years ago
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An angle measures 14° more than the measure of its complementary angle. What is the measure of each angle?
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Answer:Complementary angles are two angles whose degree measurements add up to 90 degrees. The first angle would be (x + 14.4) and its complementary angle would be x. Therefore, you would set up this problem as: x + (x + 14.4) = 902x + 14.4 = 902x = 75.6 x = 37.8  (one angle)And (x + 14.4) = 52.2 (other angle). 

To check: 37.8 + 52.2 = 90

Step-by-step explanation:

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Answer:

10:48 pm will be your answer

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Answer:

D. x = -1.

Step-by-step explanation:

I have attached an explanation to your problem. Please see the attachment  below.

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