Answer:
when heat is add to something that that odject gets hot or it turns into a gas or it milces
Explanation:
Answer:
Basic or alkaline
Explanation:
ph 7 is neutral
below 7 is acidic
above 7 is basic or alkaline
Protons goes in the blank. the word can be used for both.
This problem is describing the equilibrium whereby hydrofluoric acid decomposes to hydrogen and fluorine gases at 298 K whose equilibrium constant is 8.70x10⁻³, the equilibrium concentrations of all the reactants are both 1.33x10⁻³ M and asks for the initial concentration of hydrofluoric acid which turns out to be 2.86x10⁻³ M.
Then, we can write the following equilibrium expression for hydrofluoric acid once the change,
, has taken place:
![[HF]=[HF]_0-2x](https://tex.z-dn.net/?f=%5BHF%5D%3D%5BHF%5D_0-2x)
Now, since both products are 1.33x10⁻³ M we infer the reaction extent is also 1.33x10⁻³ M, and thus, we can calculate the equilibrium concentration of HF via the law of mass action (equilibrium expression):
![8.70x10^{-3}=\frac{(1.33x10^{-3} M)^2}{[HF]} }](https://tex.z-dn.net/?f=8.70x10%5E%7B-3%7D%3D%5Cfrac%7B%281.33x10%5E%7B-3%7D%20M%29%5E2%7D%7B%5BHF%5D%7D%20%7D)
![[HF]=\frac{(1.33x10^{-3} M)^2}{8.70x10^{-3}} }=2.03x10^{-4}M](https://tex.z-dn.net/?f=%5BHF%5D%3D%5Cfrac%7B%281.33x10%5E%7B-3%7D%20M%29%5E2%7D%7B8.70x10%5E%7B-3%7D%7D%20%7D%3D2.03x10%5E%7B-4%7DM)
Finally, the initial concentration of HF is calculated as follows:
![[HF]_0=[HF]+2x=2.033x10^{-4}+2*(1.33x10^{-3})=2.86x10^{-3}M](https://tex.z-dn.net/?f=%5BHF%5D_0%3D%5BHF%5D%2B2x%3D2.033x10%5E%7B-4%7D%2B2%2A%281.33x10%5E%7B-3%7D%29%3D2.86x10%5E%7B-3%7DM)
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