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2 years ago

Write a short note on all the planets orbiting the sun?

Geography

1 answer:

Darina [25.2K]2 years ago

5 0

Answer:

All the planets in our solar system revolve around the sun. The closer the planet is to the sun the shorter it takes for the planet to go around the sun. Us on earth takes 365 days to do a full rotation around the sun. Planets like jupiter though take longer to go around the sun

Explanation:

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The hydrosphere is composed of all of the ________________ on or surrounding the Earth. A. minerals B. air C. water D. life

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D life hope that’s right

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3 years ago

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Due to the ______ effect, the surface wind is deflected to the ______ in the Northern Hemisphere, and to the ______ in the South

fiasKO [112]

Answer: Coriolis, Right, left

Explanation:

Due to the Coriolis effect, the surface wind is deflected to the Right in the Northern Hemisphere, and to the leftin the Southern Hemisphere

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3 years ago

Two large rivers that feed directly into the amazon

Aleksandr [31]

The Negro and Madeira Rivers feed into the Amazon.

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4 years ago

How does the tropical climate of the Amazon River Basin MOST LIKELY affect vegetation?

elixir [45]

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3 years ago

. If the fastest passenger aircraft can fly 0.45 km/s (1000 mph), how long would it take to reach the sun? The galactic center?

nadezda [96]

Answer:

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The passenger aircraft would take $1.733\times 10^{10}$ years to reach the gallactic center.

Explanation:

The distance to the sun from the Earth is approximately equal to $1.496\times 10^{8}\,km$ , if the passenger travels at constant speed, then the time needed to reach the sun is calculated by the following kinematic formula:

$\Delta t = \frac{s}{v}$ (1)

Where:

$s$ - Travelled distance, measured in kilometers.

$v$ - Speed of the passenger aircraft, measured in kilometers per second.

$\Delta t$ - Travelling time, measured in seconds.

If we know that $s = 1.496\times 10^{8}\,km$ and $v = 0.45\,\frac{km}{s}$ , then the travelling time is:

$\Delta t = \frac{1.496\times 10^{8}\,km}{0.45\,\frac{km}{h} }$

$\Delta t = 3.324\times 10^{8}\,s$

$\Delta t = 3847.736\,days$

$\Delta t = 10.542\,years$

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The distance between the Earth and the galactic center is approximately equal to $2.460\times 10^{17}\,km$ . If the passenger travels at constant speed and if we know that $s = 2.460\times 10^{17}\,km$ and $v = 0.45\,\frac{km}{s}$ , then the travelling time is:

$\Delta t = \frac{2.460\times 10^{17}\,km}{0.45\,\frac{km}{s} }$

$\Delta t = 5.467\times 10^{17}\,s$

$\Delta t = 6.327\times 10^{12}\,days$

$\Delta t = 1.733\times 10^{10}\,years$

The passenger aircraft would take $1.733\times 10^{10}$ years to reach the gallactic center.

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3 years ago