Question

14 POINTS TO HELP ME

Answer 1

Answer: I Think It Is Greater Than Or Equal To -9

Step-by-step explanation: The given function is:

f(x)x^2+2x-8

We complete the square to write this function in the form:

f(x)=a(x-h)^2+k

We add and subtract the square of half the coefficient of x.

f(x)=x^2+2x+1^2-1^2-8

f(x)=(x=1)^2-9

The vertex of this function is (h,k) which is (-1,-9)

The equation of axis of symmetry is x=h

But h=-1, hence the axis of symmetry isx=-1

To find the x-intercepts, we put f(x)=0

(x+1)^2-9=0

(x+1)^2=9

x+1=the square root of 9

x=-4, 2

The x-intercepts are:(

-4,0) and (2,0)

The given function is a polynomial function, the domain is all real numbers

The function has a minimum value of y=-9.

Therefore the range is y|y is greater that or less than -9