(See attached)
AO^2 = side a^2 - BO^2
AO^2 = 41^2 -40^2
AO^2 = 1,681 -1600
AO^2 = 81
AO = 9
DO^2 = side b^2 -BO^2
DO^2 = 50^2 -40^2
DO^2 = 2,500 -1,600
DO^2 = 900
DO = 30
Diagonal AD = AO + DO = 9 + 30 = 39 inches
Source:
http://www.1728.org/quadkite.htm
Answer:
1³ = 1
2³ = 8
3³ = 27
4³ = 64
5³ = 125
6³ = 216
Step-by-step explanation:
Jelly beans - $0.98 per pound
chocolate drops - $0.67 per pounds
terri's bag = 2.1 pounds and $1.56
p = represents the pounds jelly beans.
c = represents the pounds in chocolate drops
p + c = 2.1
0.98p + 0.67c = 1.56
c = 2.1 - p ; number of pounds of chocolate drops
0.98p + 0.67(2.1 - p) = 1.56
0.98p + 1.41 - 0.67p = 1.56
0.98p - 0.67p = 1.56 - 1.41
0.31p = 0.15
p = 0.15/0.31
p = 0.48 pounds of jelly beans
c = 2.1 - 0.48
c = 1.62 pounds of chocolate drops.
Answer:
The fraction of the students play soccer = 
Step-by-step explanation:
Given - In the town of Destin, 2/3 of the students in middle school participate in organized sports after school.
To find - If 3/5 of them play soccer, what fraction of the students play soccer? Enter your answer in simplest form
Solution -
Let us assume that,
Total number of students in the middle school = 3x
Now,
Given that
2/3 of the students in middle school participate in organized sports after school.
So,
Total students participated in organized sports = (2/3)×3x
= 2x
⇒Total students participated in organized sports = 2x
Now,
Given that,
3/5 of them play soccer
So,
Total players who play soccer = (3/5)×2x
= 6x/5
⇒Total players who play soccer = 6x/5
Now,
The fraction of total students play soccer = (6x/5) ÷ (3x)
= 
=
∴ we get
The fraction of the students play soccer =
Answer:
longer leg is 30 inches
Step-by-step explanation:
