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coldgirl [10]
2 years ago
15

Evaluate the following, if a=7, b=3, c=2

Mathematics
1 answer:
Zinaida [17]2 years ago
4 0

Answer:

Step-by-step explanation:

a^2 - 5bc - 1

a = 7

b = 3

c = 2

7^2 - 5*3*2 - 1

49 - 30 - 1

18

You might be interested in
The function f(x) varies inversely with x and f(x)=-15 when x=30
meriva
F(x) is the function that represents a given equation. It is defined more specifically by rules or conditions to satisfy the whole formula/equation.

In this case, f(x) has an inverse proportion with x (e.g. f(x) = 1/x). The second parameter says that f(x) = -15 when x is 30. Given that condition, just look for the formula, among the choices, that will result to -15 when x = 30. The answer is:

D. f(x) = -450/x

This is just -450/30 = -15
3 0
4 years ago
2. The senior class is having a fundraiser to help pay for the senior trip. Selling a box of chocolates yields a profit of $2.45
BaLLatris [955]

Answer:

Step-by-step explanation:

350 chocolate     1599 of cookies

Step-by-step explanation:

c= box of chocolates

k=box of coockies

k< 550+3c , so   k-3c<550              

 k+c< 1950

 k-3c<550

I will multiply  the second by 3

k -  3c <  550

3k +3c <  5850

ADD BOTH

4k  <  6400

k  <   1600    Cookies should be less than 1600

Since cookies yield more than chocolates , to maximize profit they need to sell the maximum amount of cookies they can

1599 +350= 1949  (less than 1950)

The amount of cookies produced must be no more than 550 boxes plus 3 times the number of chocolates produced.

1599< 3(350) +550= 1050+550=1600)

1599<1600

1599 is at least double of 350 (it could be more than double)

4 0
3 years ago
Can somebody plz help answer these questions correctly (only if u know how) thanks ! :D
cricket20 [7]

Answer:

21. 12

22. 42

23. 15

24. 6

25. 12

26. 24

6 0
2 years ago
Read 2 more answers
Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random
Katyanochek1 [597]

Answer:

a) Null hypothesis: \mu_A =\mu_B =\mu C

Alternative hypothesis: \mu_i \neq \mu_j, i,j=A,B,C

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 =20.5  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =12.333  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8.16667  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=df_{within}=k-1=3-1=2 where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-K=3*6-3=15.

And the total degrees of freedom would be df=N-1=3*6 -1 =15

The mean squares between groups are given by:

MS_{between}= \frac{SS_{between}}{k-1}= \frac{12.333}{2}=6.166

And the mean squares within are:

MS_{within}= \frac{SS_{within}}{N-k}= \frac{8.1667}{15}=0.544

And the F statistic is given by:

F = \frac{MS_{betw}}{MS_{with}}= \frac{6.166}{0.544}= 11.326

And the p value is given by:

p_v= P(F_{2,15} >11.326) = 0.00105

So then since the p value is lower then the significance level we have enough evidence to reject the null hypothesis and we conclude that we have at least on mean different between the 3 groups.

b) (\bar X_B -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_B}{n_B} +\frac{s^2_C}{n_C}}

The degrees of freedom are given by:

df = n_B +n_C -2= 6+6-2=10

The confidence level is 99% so then \alpha=1-0.99=0.01 and \alpha/2 =0.005 and the critical value would be: t_{\alpha/2}=3.169

The confidence interval would be given by:

(43.333 -41.5) - 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}= 0.321

(43.333 -41.5) + 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}=3.345

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part a  

Null hypothesis: \mu_A =\mu_B =\mu C

Alternative hypothesis: \mu_i \neq \mu_j, i,j=A,B,C

If we assume that we have 3 groups and on each group from j=1,\dots,6 we have 6 individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 =20.5  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =12.333  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8.16667  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=df_{within}=k-1=3-1=2 where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-K=3*6-3=15.

And the total degrees of freedom would be df=N-1=3*6 -1 =15

The mean squares between groups are given by:

MS_{between}= \frac{SS_{between}}{k-1}= \frac{12.333}{2}=6.166

And the mean squares within are:

MS_{within}= \frac{SS_{within}}{N-k}= \frac{8.1667}{15}=0.544

And the F statistic is given by:

F = \frac{MS_{betw}}{MS_{with}}= \frac{6.166}{0.544}= 11.326

And the p value is given by:

p_v= P(F_{2,15} >11.326) = 0.00105

So then since the p value is lower then the significance level we have enough evidence to reject the null hypothesis and we conclude that we have at least on mean different between the 3 groups.

Part b

For this case the confidence interval for the difference woud be given by:

(\bar X_B -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_B}{n_B} +\frac{s^2_C}{n_C}}

The degrees of freedom are given by:

df = n_B +n_C -2= 6+6-2=10

The confidence level is 99% so then \alpha=1-0.99=0.01 and \alpha/2 =0.005 and the critical value would be: t_{\alpha/2}=3.169

The confidence interval would be given by:

(43.333 -41.5) - 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}= 0.321

(43.333 -41.5) + 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}=3.345

7 0
3 years ago
A student spends the same amount each week for bus fare. In 6 weeks, he spends $81. Which equation shows this relationship? Let
Pavel [41]

Answer:

The answer is 13.50x

Step-by-step explanation:

81 / 6=13.5 per week

8 0
3 years ago
Read 2 more answers
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