3 years ago

Help!

1 answer:

4 0

C because the base id the bottom which is 5 ( count the boxes at the bottom ) and the height is 9 is the side the long side

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A six sided number cube is laveled with number from 1 to 6 . If a student tolls the cube 150 times howany times should they expe

andrey2020 [161]

Answer:

75 times

Step-by-step explanation:

6 sided die - 1,2,3,4,5,6

3 of these numbers are even

P(even) = 3/6 = 1/2

1/2 * 150 = 75

7 0

3 years ago

Find that image of P(-2,4) under a translation along the vector (6,5)

ollegr [7]

Answer:

P'(4, 9)

Step-by-step explanation:

Add the translation vector to the point:

P' = P +(6, 5) = (-2, 4) +(6, 5) = (-2+6, 4+5)

P' = (4, 9)

4 0

3 years ago

Which answer is equal to ( sqrt 7)^3?<br> A.7 3/2<br> B.7 2/3<br> C.7 1/6<br> D.7 1/3

horrorfan [7]

Try D As your Answer.

6 0

3 years ago

Read 2 more answers

If f(x) is differentiable for the closed interval [−4, 0] such that f(−4) = 5 and f(0) = 9, then there exists a value c, −4 <

Pavel [41]

$\bf \textit{mean value theorem}\\\\
f'(c)=\cfrac{f(b)-f(a)}{b-a}\qquad 
\begin{cases}
a=-4\\
b=0
\end{cases}\implies f'(c)=\cfrac{f(0)-f(-4)}{0-(-4)}
\\\\\\
f'(c)=\cfrac{9-5}{0+4}\implies f'(c)=\cfrac{4}{4}\implies f'(c)=1$

4 0

3 years ago

The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability d

ollegr [7]

Answer: 0.70

Step-by-step explanation:

Given : The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution:

x 0 1 2 3 4 5

P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05

Using the above probability distribution , the the probability that in a given week there will be at most 3 accidents is given by :_

$P(\leq3)=P(0)+P(1)+P(2)+P(3)\\\\=0.20+0.30+0.20=0.70$

Hence, the required probability = 0.70

7 0

3 years ago