means to say that for any given 
, we can find 
such that anytime 
(i.e. the whenever 
is "close enough" to 5), we can guarantee that 
(i.e. the value of 
is "close enough" to the limit value).
What we want to end up with is
Dividing both sides by 3 gives
which suggests 
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let be given. Then if
and so the limit is 7. QED
I can help answer if you could post a picture of the second map
Answer:
make him brainliest not me
Step-by-step explanation:
asd ad asd a da
Answer:
They are hard and you Just have to follow the steps of solbing them
Step-by-step explanation:
B=7
3(b-4)+5b=44
3b-12+5b=44
8b=44+12
8b=56
b=7
