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Novay_Z [31]
3 years ago
14

Which ordered pairs are solutions to the equation 2x + 10y = 12?

Mathematics
2 answers:
White raven [17]3 years ago
5 0
A pair could be (4,2/5)
vovangra [49]3 years ago
4 0

Answer:

(4,2/5) (−5,11/5)

Step-by-step explanation:

To determine which pairs are solutions, substitute the coordinates into the left side of the equation and if equal to the right side then they are solutions.

(7, - 2)

2(7) + 10(- 2) = 14 - 20 = - 6 ≠ 12 → (7, - 2) is not a solution

(- 5, - 4)

2(- 5) + 10(- 4) = - 10 - 40 = - 50 ≠ 12 → (- 5, - 4) is not a solution

(4,  )

2(4) + 10() = 8 + 4 = 12 → hence solution

(- 5,  )

2(- 5) + 10( ) = - 10 + 22 = 12 → hence solution

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zalisa [80]

Answer:

Step-by-step explanation:

A) 3x−12≥15

3x ≥ 15 + 12

3x ≥ 27

or x≥ 9

B) 2x−5≤9

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2x ≤ 14

or x ≤ 7

C) 5x+8≤53

5x ≤ 53 -8

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or x ≤ 9

D) 3x−5≥16

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Have a good day!

8 0
3 years ago
Reduce the fraction to lowest terms m^2/m^2-n^2
Softa [21]

Answer:

\boxed{\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}}

Step-by-step explanation:

Factor \bold{m^2-n^2}

\bold{\left(m+n\right)\left(m-n\right)}

Rewrite Equation

\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}

4 0
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Step-by-step explanation:

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