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2 years ago

Help..............lllllllllllllllllll

Mathematics

2 answers:

polet [3.4K]2 years ago

8 0

Answer:

4 pepperoni pizzas

Step-by-step explanation:

Bogdan [553]2 years ago

8 0

3 cheese => 1 pepperoni

12cheese (3x4) => 4 (1x4) pepperoni

You might be interested in

A) Calculate an estimate for the mean height of the students. 129.3 cm

Sedbober [7]

Answer:

(a) Y = 129.3x (b) It is an estimate as it may not be a true reflection of a student's height

Step-by-step explanation:

(a) Estimate of the mean height is the sum of the heights of all the students divided by the total number of students.

The question however needs more information for its estimation as 129.3cm is representative and may be the mean height but it was not stated.

However, assuming it is the mean height,

Let the total number of students be x

while Y is the sum of all individual student heights

Mathematically, mean = Y/x

Therefore 129.3 = Y/ x

implying that Y = 129.3x

(b) It is an estimate because computation of the mean gives an average which may not be an exact value. For example, the mean here is 129.3 whereas there will be many heights greater than that and some lesser than that and obviously, there may be no student with height of 129.3 hence it is an estimate.

8 0

3 years ago

Find the Midpoint of a segment with the following endpoints. Type your

exis [7]

Answer:

3/2;5/2

Step-by-step explanation:

-1+4/2 ; 4+1/2

3/2 ; 5/2

6 0

2 years ago

A random sample of 12 recent college graduates reported an average starting salary of $54,000 with a standard deviation of $6,00

Marianna [84]

Answer: a.) $50188 to $57812

Step-by-step explanation: Confidence Interval (CI) is an interval of values in which we are confident the true mean is in.

The interval is calculated as

x ± $z\frac{s}{\sqrt{n} }$

a. For a 95% CI, z-value is 1.96.

Solving:

54,000 ± $1.96.\frac{6000}{\sqrt{12} }$

54,000 ± $1.96\frac{6000}{3.464}$

54,000 ± 1.96*1732.102

54,000 ± 3395

This means the interval is

50605 < μ < 57395

With a 95% confidence interval, the mean starting salary of college graduates is between 50605 and 57395 or from 50188 to 57812$.

b. The mean starting salary for college students in 2017 is $50,516, which is in the confidence interval. Therefore, since we 95% sure the real mean is between 50188 and 57812, there was no significant change since 2017.

4 0

2 years ago

How do you solve 1/3 of 3/4 of a fraction

Trava [24]

1 1/12

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(1/3, 3/4) = 12

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(13×44)+(34×33)=?

Complete the multiplication and the equation becomes

4/12+9/12=?

The two fractions now have like denominators so you can add the numerators.

Then:

4+9/12=13/12

This fraction cannot be reduced.

The fraction

13/12

is the same as

13÷12

Convert to a mixed number using

long division for 13 ÷ 12 = 1R1, so

1312=1 1/12

Therefore:

13+34=1 11/2

5 0

3 years ago

The following data pairs represent the average temperature x (in degrees Fahrenheit) and electricity

elena55 [62]

Answer:

The correct answer is C. r = 0 because is most likely the closest to the correlation coefficient of the data.

Step-by-step explanation:

Using Excel, we captured the data provided for the 12 different homes for calculating the correlation coefficient manually, this way:

n = 12

∑x = 904

∑y = 2,169

∑xy = 167,532

∑x² = 69,552

∑y² = 404,615

r = [n *∑xy - (∑x * ∑y)]/[√(n * ∑x² - (∑x)²) * (n * ∑y² - (∑y)²)]

Replacing with the real values, we have:

r = [12 * 167,532 - (904 * 2,169)]/[√(12 * 69,552 - 904²) * (12 * 404,615 - 2,169²)]

r = [2'010,384 -1'960,776]/[√(834,624 - 817,216) * (4'855,380 - 4'704,561]

r = 49,608/√17,408 * 150,819

r = 49,608/ 51'239.215

r = 0.00097

The correct answer is C. r = 0 because is most likely the closest to the correlation coefficient of the data.

4 0

2 years ago

Read 2 more answers