The mean is the average value of the numbers given in the series
The mode is the number that is appears more than any other number given in the series
Step-by-step explanation:
Given challenge is make a list of 5 numbers
The list of 5 number is = 8,10,12,15,15
![Mean value = (8+10+12+15+15)/5 =60/5 = 12](https://tex.z-dn.net/?f=Mean%20value%20%3D%20%288%2B10%2B12%2B15%2B15%29%2F5%20%3D60%2F5%20%3D%2012)
so required mean is 12 has been computed
Mode = 15 ( the number 12 is appeared in two times 8,10,12,15,15)
Final answer
The required numbers are = 8,10,12,15,15
Answer:
P = 40.56 ft
Step-by-step explanation:
The figure is composed of a rectangle and half circle
The perimeter of the figure = the length of the borders round the figure
= W + 2L + ½(perimeter of full circle)
W = 8 ft
L = 10 ft
½(perimeter of circle) = ½(πd) = ½(3.14*8)
= 12.56 ft
Plug in the values
Perimeter of the figure = 8 + 2(10) + 12.56
= 8 + 20 + 12.56
= 40.56 ft
So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Harap awak faham hehehe kalau jawapan betul bagi brainliest yer hehehe