f(x) = (x - 
)² - 
the equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= - 
f(x) = x² - 11x + 9 is in standard form
with a = 1, b = - 11 and c = 9
= - 
=
substitute this value into the equation for y- coordinate
y = ()² - 11() + 9
= 
- 
+ 
= -
f(x) = (x - )² - ← in vertex form
1 tens cause 1 ten plus one 1 tenth is 11 and 11-10 is 1 right
Answer:
Step-by-step explanation:
Hope this helps u !!
Answer:
The first picture presented showing to rows of dots in a somewhat straight line.
Step-by-step explanation:
For the first one it is, j<<span>−<span>13
Second one, </span></span>n<<span>−<span>8
</span></span>Third one, k><span>−<span>50</span></span><span>
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