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3 years ago

Prove that congruent triangles have congruent corresponding altitudes. I NEED ANSWER ASAP PLZZZZZZZZZZZZZZZZZZZZZ

1 answer:

8 0

Corresponding altitudes are corresponding parts. They are congruent because ... Corresponding parts of congruent triangles are congruent. (CPCTC)

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2 years ago

kherson [118]

Answer:

$sinA=\frac{opposite}{hypotenuse}$

Step-by-step explanation:

Soh-cah-toa is a great way to remember:

$sin=\frac{opposite}{hypotenuse}\\ cin=\frac{adjacent}{hypotenuse}\\ tan=\frac{opposite}{adjacent}$

You just remember the first letters : sine= opposite/hypotenuse , for example.

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3 years ago

Yuliya22 [10]

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2 years ago

Arte-miy333 [17]

Answer:

$6\sqrt{5}$

Step-by-step explanation:

In any right triangle, the Pythagorean theorem states:

$a^2+b^2=c^2$ , where $a$ and $b$ are two legs of the triangle and $c$ is the hypotenuse.

Plugging in given values, we have:

$12^2+VU^2=18^2,\\144+VU^2=324,\\VU^2=180,VU=\sqrt{180}=\sqrt{36}\cdot \sqrt{5}=\boxed{6\sqrt{5}}$

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2 years ago

Arturiano [62]

Answer:

0.82

اولويات الضرب و القسمه

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2 years ago