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2 years ago

The radius of a circle is 1 mm. What is the circle's circumference?

Mathematics

2 answers:

Keith_Richards [23]2 years ago

7 0

Answer:

6.283 mm

Step-by-step explanation:

the equation for circumference is 2 $\pi$ r

if the radius is 1 then insert it

c=2 $\pi$ (1)

c=6.283 mm

hodyreva [135]2 years ago

3 0

Answer:

C≈6.28mm

Step-by-step explanation:

C=2πr

= 2·π·1≈6.28319mm

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Answer to this math question please

shtirl [24]

Answer:

Step-by-step explanation:

8 times 3 TwT

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2 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

2 years ago

using the midpoint formula, solve for the midpoint of the segment with these pairs of endpoints (-11,30) and (-26,-2)

REY [17]

Answer:

Midpoint is $(\frac{-37 }{2}, 14)$

Step-by-step explanation:

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

= $(\frac{-11 -26}{2}, \frac{30 - 2 }{2})$

= $(\frac{-37 }{2}, \frac{28 }{2})$

= $(\frac{-37 }{2}, 14)$

Midpoint is (-37/2, 14)

3 0

2 years ago

Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.

FrozenT [24]

You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:

Note that if   <span>ax^2+bx+5=0 then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

- b plus sqrt( b^2 - 20a )
d =  ------------------------------------
2a

and

</span> - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?

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3 years ago

When you SWITCH the HYPOTHESIS and the CONCLUSION you create the _________ statement.

Gekata [30.6K]

Answer:

CONVERSE

Step-by-step explanation:

When you switch hypothesis and conclusion you are creating what is called the CONVERSE statement.

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3 years ago

The radius of a circle is 1 mm. What is the circle's circumference? ​

The radius of a circle is 1 mm. What is the circle's circumference?