Question

(h+1)^2=16 solve using square root property

Answer 1

Answer:

$h=3, \ h=-5$

Step-by-step explanation:

$(h+1)^2=16$

$(h+1)^2=16$

$\sqrt{(h+1)^2} = \±\sqrt{16}$                    <== you take the square root of both sides

$(h+1) = \±\ 4$                            <== you take the square root of both sides

$(h+1) = +\ 4, \ (h+1) = -\ 4$    <== separate into 2 equations and solve

$h+1 = 4, \ h+1 = -\ 4\\\\. \ -1 -1, \ \ \ \ -1\ \ \ \ -1\\\\h=3, \ h=-5$

Hope this helps!

Answer 2

Answer: h = 3

Step-by-step explanation:

(h+1)² = 16

h+1 = √16

h+1 = 4

h = 3

Hope this helped :)