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Andrews [41]
2 years ago
13

HELP PLEASE ASAP I WILL MARK BRAINLIEST

Mathematics
1 answer:
prisoha [69]2 years ago
3 0

Answer:

BC = 24

Step-by-step explanation:

FD = 36, FE = 15 and CD = 18

By secant theorem.

DE • DF = CD • DB

(36 - 15) • 36 = 18 • DB

DB = 42

BC = DB - CD

BC = 42 - 18

BC = 24

PLEASE MARK ME AS BRAINLIEST AND HAVE A NICE DAY :)

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80 minutes... or an hour and 20 minutes

Step-by-step explanation:

55+25 = 80. an hour is 60 minutes long

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Answer:

x = 15.3°

Step-by-step explanation:

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sin(x)=\dfrac{O}{H} \ \ \ \ \ cos(x)=\dfrac{A}{H} \ \ \ \ \ tan(x)=\dfrac{O}{A}

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Can a unit rate be a fraction
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Yes it can, it has to be a fraction
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Illusion [34]

Answer:

<h2><u>question 1</u></h2>

n^{2} - 20n -96 = 0

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u />x^{2} + 12 x = 48<u />

in the form ax^{2}  +bx +c = 0

= x^{2} +12x - 48

make use of the formula :

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

replace values to make 2 equations :

1.\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1} = 3.17

2.\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1} = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u />x^{2} -14x+40=0<u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

<u />5b^{2} -20b-18 = 7<u />

in the form ax^{2}  +bx +c = 0

this becomes 5b^{2} -20b-18-7

= 5b^{2} -20b-25

can simplify by 5

= b^{2} -4b-5 =0\\

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