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3 years ago

Which equation represents a line that is parallel to the line whose equation is y=-3x

2 answers:

7 0

Any line whose equation is

y = -3x + (any positive or negative number)

is parallel to the line whose equation is y = -3x .

BabaBlast [244]3 years ago

6 0

Any line that has the equation in the form y = -3x + c, where c is any real number, is parallel to the equation y = -3x

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Kaylee's gross income is $3,200 per month. Of this amount 25% is taken out for taxes and other required deductions. How much is

andrew11 [14]

Answer: $\$2400$

Step-by-step explanation:

Given

Kaylee's gross income is $\$32,000\text{per month}$

$25\%$ is taken out for taxes and other required deduction

left amount is

$\Rightarrow 3200-25\%\times 3200\\\Rightarrow 3200(1-0.25)=\$2400$

So, her take-home pay is $\$2400$

4 0

3 years ago

The figure shows two parallel lines cut by a transversal.

max2010maxim [7]

Answer: D and E

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th

NeX [460]

As long as Loren drove, the law of motion was

$200 = st_1 \implies t_1 = \dfrac{200}{s}$

As long as Loid drove, the law of motion was

$100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}$

So, the total time they took is

$t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}$

Had Loren driven the whole time, the law of motion would have been

$300=st_3 \implies t_3 = \dfrac{300}{s}$

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

$t_3 = t_1+t_2-0.5$

This translates into

$\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}$

If we subtract 200/s from both sides, we have

$\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}$

We can simplify the right hand side by summing the two fractions:

$\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}$

So, we have to solve

$\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}$

If we cross multiply the denominators, we have

$200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0$

Which yields the solutions

$s=-40,\quad s=50$

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0

3 years ago

Read 2 more answers

The answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Step2247 [10]

Yeah The Answer Would Be A=299

6 0

3 years ago

Pls help this is to confusing for me

zepelin [54]

Answer:

Reduction; scale factor of $\frac{1}{3}$ .

Step-by-step explanation:

Hope this helps!

8 0

3 years ago